小编Arc*_*ill的帖子

假设我有整数89,如何打印出89的ASCII值,即Y,而不是打印出数字89？

我目前正在尝试使用 Tkinter 包使用 Python 来学习制作简单的 GUI。

我为待办事项列表编写了这个程序：

import tkinter
import tkinter.messagebox
import pickle

root = tkinter.Tk()
root.title = ("To Do List")

def add_task():
    task = entry_task.get()
    if task not in ["", "Do nothing"]:
        listbox_tasks.insert(tkinter.END, task)  
        entry_task.delete(0, tkinter.END)
    else:
        tkinter.messagebox.showwarning(title="Warning!", message="Doing nothing is not an option!.")

def delete_task():
    try:
        task_index = listbox_tasks.curselection()[0]
        listbox_tasks.delete(task_index)
    except:
        tkinter.messagebox.showwarning(title="Warning!", message="You need to select a task to delete.")

def load_tasks():
    try:
        tasks = pickle.load(open("Aufgaben.txt", "rb"))  # reading binary
        listbox_tasks.delete(0, tkinter.END)
        for task in tasks:
            listbox_tasks.insert(tkinter.END, task) …