我有以下数组:
var example = [
function() { /* hello */ },
function() { /* goodbye */ }
];
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我使用delete example[0];并留下以下结果:
var example = [
1: function() { /* goodbye */ }
];
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有比这更好的解决方案delete吗?或者有一种简单的方法来修复数组中的索引?(我有jQuery可供我使用)
编辑:我修复了示例数组.索引就是这样的例子.
PHP的示例输出:
{
"RootName_0":{"Id":1,"ValId":1,"Value":"Colour","Text":"Blue"},
"RootName_1":{"Id":1,"ValId":2,"Value":"Colour","Text":"Red"}
}
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我如何使用Backbone.js或jQuery仅具有:
[
{"Id":1,"ValId":1,"Value":"Colour","Text":"Blue"},
{"Id":1,"ValId":2,"Value":"Colour","Text":"Red"}
]
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如果使用PHP编辑JSON更容易,那就这样吧.
我已经厌倦了四处寻找足够近的例子,时间可以获得一些快速的帮助!这是我的代码:
preg_match_all( '#<li.*?>.*?</li>#s', $card_html, $activity );
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我想修改它以便<li.*?>排除这个词Unplayed.(这个词出现在之后.*?和之前>.
编辑:
Want to catch: http://gamercard.xbox.com/en-US/Stallion83.card
<li >
<a href="http://live.xbox.com/en-us/GameCenter/Achievements?title=1464993792&compareTo=Stallion83">
<img src="http://tiles.xbox.com/tiles/vD/fP/1Gdsb2JhbA9ECgUPGgIfVl9TL2ljb24vMC84MDAwIAAAAAAAAPvgN6M=.jpg" alt="F.E.A.R. 3" title="F.E.A.R. 3" />
<span class="Title">F.E.A.R. 3</span>
<span class="LastPlayed">6/24/2011</span>
<span class="EarnedGamerscore">415</span>
<span class="AvailableGamerscore">1000</span>
<span class="EarnedAchievements">23</span>
<span class="AvailableAchievements">50</span>
<span class="PercentageComplete">46%</span>
</a>
</li>
<li class="Complete" >
<a href="http://live.xbox.com/en-US/GameCenter/Achievements?title=1096157212&compareTo=Im%20RedJ">
<img src="http://tiles.xbox.com/tiles/HI/L4/1Gdsb2JhbA9ECgQJGgYfVl4gL2ljb24vMC84MDAwIAAAAAAAAPvXggM=.jpg" alt="Call of Duty: WaW" title="Call of Duty: WaW" />
<span class="Title">Call of Duty: WaW</span>
<span class="LastPlayed">6/21/2011</span>
<span class="EarnedGamerscore">1500</span>
<span class="AvailableGamerscore">1500</span>
<span class="EarnedAchievements">66</span>
<span class="AvailableAchievements">66</span> …Run Code Online (Sandbox Code Playgroud) $a = array(
0 => array( 'one' => 1, 'two' => 2 ),
1 => array( 'one' => 3, 'two' => 4 ),
2 => array( 'one' => 5, 'two' => 2 )
);
$c = count( $a );
$r = array();
for ( $i = 0; $i < $c; $i++ )
{
if ( $a[$i]['two'] == 2 )
$r[] = $a[$i];
}
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有没有更清洁的方法来完成上述所有工作?
我能找到的人们使用的唯一例子$.each是html样本,而这不是我想要的.我有以下对象:
var obj = {
obj1: 39,
obj2: 6,
obj3: 'text'
obj4: 'text'
obj5: 0
};
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我像这样循环遍历对象:
$(array).each(function(index, value) {
// ...
});
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我想按obj3和排序obj4.最好不要使用异步方法,如何在输出之前(或期间)对结果进行排序?(我也不想两次循环,因为在任何给定的时间都可能有数百个.
我正在尝试构建一个自定义版本的GyazoWin Use of MFC:Use MFC in a Static Library,它会产生大量的参考错误.
我如何安抚Visual Studio,以便使用静态链接库进行构建?
更新
我设法将user32添加到链接库(我认为),现在我只有1/3的错误.谁能说出我现在缺少的图书馆?
Error 2 error LNK2019: unresolved external symbol __imp__BitBlt@36 referenced in function "long __stdcall WndProc(struct HWND__ *,unsigned int,unsigned int,long)" (?WndProc@@YGJPAUHWND__@@IIJ@Z) S:\Software\Microsoft\Visual Studio\Projects\Completed (New)\gyazowin\gyazowin\gyazowin.obj gyazowin
Error 3 error LNK2019: unresolved external symbol __imp__CreateCompatibleBitmap@12 referenced in function "long __stdcall WndProc(struct HWND__ *,unsigned int,unsigned int,long)" (?WndProc@@YGJPAUHWND__@@IIJ@Z) S:\Software\Microsoft\Visual Studio\Projects\Completed (New)\gyazowin\gyazowin\gyazowin.obj gyazowin
Error 4 error LNK2019: unresolved external symbol __imp__CreateCompatibleDC@4 referenced in function "long __stdcall WndProc(struct HWND__ *,unsigned int,unsigned int,long)" (?WndProc@@YGJPAUHWND__@@IIJ@Z) …Run Code Online (Sandbox Code Playgroud) private static transient JavaPlugin myPlugin = null;
public SomeClass(JavaPlugin plugin) {
if (myPlugin == null) myPlugin = plugin;
}
public <T> T getPlugin(Class<? extends JavaPlugin> plugin) {
return (T)myPlugin; // return casted version of "myPlugin" form above
}
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在下面的行中调用它可以正常工作,并且尝试使用不扩展JavaPlugin的类将引发编译时错误.但是我怎样才能使上述功能无需工作呢@SuppressWarnings("unchecked")?
MyPlugin nc = this.getPlugin(my.main.package.MyPlugin.class);
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<li class="active active"><a href="http://netcoding.net/indev/sample-page/">Sample Page</a></li>
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请注意,所显示的课程可能会发生变化并处于不同的位置.
我有两个兄弟项目ProjectA和ProjectB那都是下Parent。Parent 基本上只是一个文件夹,并且对于两个子项目都有共同的 build.gradle 设置。
ProjectB 在编译时依赖于 ProjectA 中的代码,但 ProjectA 是单独构建的,并包含一个 META-INF 目录。构建 ProjectB 时,我收到一个java.lang.SecurityException: Invalid signature file digest for Manifest main attributes。正如您在下面看到的,我已从 ProjectB 中删除了 zipTree 调用,但不确定如何解决此问题。非常感谢一些帮助。
请记住,两个项目都必须构建自己的 JAR,而 ProjectA 必须遮蔽下面看到的两个依赖项。
父设置.gradle:
rootProject.name = "Parent"
include ":ProjectA", ":ProjectB"
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父 build.gradle:
allprojects {
buildscript {
repositories {
jcenter()
maven {
name = "forge"
url = "https://files.minecraftforge.net/maven"
}
maven {
name = "sponge"
url = "https://repo.spongepowered.org/maven"
}
}
dependencies {
classpath "net.minecraftforge.gradle:ForgeGradle:2.3-SNAPSHOT"
classpath "org.spongepowered:mixingradle:0.6-SNAPSHOT"
} …Run Code Online (Sandbox Code Playgroud) DROP PROCEDURE IF EXISTS CreateTopic;
CREATE PROCEDURE CreateTopic
(
i_forum_id INT,
i_user_id INT,
i_title VARCHAR(255),
i_language VARCHAR(50),
i_content TEXT,
i_stickied TINYINT,
i_announce TINYINT,
i_closed TINYINT
)
BEGIN
INSERT INTO forum_topics (forum_id, user_id, title, language)
VALUES (i_forum_id, i_user_id, i_title, i_language);
SET @tid := LAST_INSERT_ID();
INSERT INTO forum_posts (topic_id, user_id, subject, content) VALUES (@tid, i_user_id, i_title, i_content);
INSERT INTO core_logs (obj_id, user_id, type, action) VALUES (@tid, i_user_id, 'Topics', 'Topic Created');
END;
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我不确定它有什么问题.MySQL告诉我各种各样的事情是不正确的,它只是不想创建.而且,参数与它们各自的表是相同的类型和长度.
在我的语法高亮显示器中,我使用正则表达式来解析不同的术语.下面是我解析PHP类的方法:
foreach ( PHP::$Classes as $class )
$code = preg_replace( "/\b{$class}\b/", $this->_getHtmlCode( $class, PHP::$Colors['class'] ), $code );
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现在,只需忽略PHP类和_getHtmlCode函数.正则表达式"/\b{$class}\b/"匹配诸如的名称count.如果我创建一个名为的变量$count,那么匹配就好了.
如何查找前面没有的类名$?