JavaScript:从json对象中删除键

Question

PHP的示例输出:

{
    "RootName_0":{"Id":1,"ValId":1,"Value":"Colour","Text":"Blue"},
    "RootName_1":{"Id":1,"ValId":2,"Value":"Colour","Text":"Red"}
}

我如何使用Backbone.js或jQuery仅具有:

[
    {"Id":1,"ValId":1,"Value":"Colour","Text":"Blue"},
    {"Id":1,"ValId":2,"Value":"Colour","Text":"Red"}
]

如果使用PHP编辑JSON更容易,那就这样吧.

Answer 1

好吧,在PHP中它很容易,只需array_values()在初始数组上使用它就"忘记"数组索引(顺便说一下,在你的情况下调用'RootName_X':

$newvalue = array_values( (array)$value );
echo json_encode($newvalue);

在javascript中,它有点棘手,但它将是:

var newvalue = [];
for(var root in value)
   newvalue.push(value[root]);

问题标题是有点混乱,因为这些当然不是标签.