小编Mat*_*ney的帖子

我正在尝试从Google Chrome扩展程序将图像上传到Picasa,并在构建POST时遇到一些麻烦.

这是谷歌指定用于将图像上传到Picasa的协议(链接):

Content-Type: multipart/related; boundary="END_OF_PART"
Content-Length: 423478347
MIME-version: 1.0

Media multipart posting
--END_OF_PART
Content-Type: application/atom+xml

<entry xmlns='http://www.w3.org/2005/Atom'>
  <title>plz-to-love-realcat.jpg</title>
  <summary>Real cat wants attention too.</summary>
  <category scheme="http://schemas.google.com/g/2005#kind"
    term="http://schemas.google.com/photos/2007#photo"/>
</entry>
--END_OF_PART
Content-Type: image/jpeg

...binary image data...
--END_OF_PART--

这就是我拼凑起来试图做到这一点,从这里借用代码和扩展"clip-it-good":

function handleMenuClick(albumName, albumId, data, tab) {
  chrome.pageAction.setTitle({
    tabId: tab.id,
    title: 'Uploading (' + data.srcUrl.substr(0, 100) + ')'
  });
  chrome.pageAction.show(tab.id);

  var img = document.createElement('img');
  img.onload = function() {
    var canvas = document.createElement('canvas');
    canvas.width = img.width;
    canvas.height = img.height;
    canvas.getContext('2d').drawImage(img, 0, 0); …

有一种socket方法可以获取给定网络接口的IP:

import socket
import fcntl
import struct

def get_ip_address(ifname):
    s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    return socket.inet_ntoa(fcntl.ioctl(
        s.fileno(),
        0x8915,  # SIOCGIFADDR
        struct.pack('256s', ifname[:15])
    )[20:24])

返回以下内容:

>>> get_ip_address('lo')
'127.0.0.1'

>>> get_ip_address('eth0')
'38.113.228.130'

是否有类似的方法来返回该接口的网络传输？我知道我可以阅读,/proc/net/dev但我喜欢套接字方法.