小编Ste*_*ven的帖子

是否可以ForEach在模板文字中返回字符串值,以便将其添加到该位置？因为如果我记录它会返回undefined.或者就像我输入的那样根本不可能？

return `<div>
                <form id='changeExchangeForViewing'>
    <label for='choiceExchangeForLoading'>Change the exchange</label>
    <div class='form-inline'>
    <select id='choiceExchangeForLoading' name='choiceExchangeForLoading' class='form-control'>

    ${Object.keys(obj).forEach(function (key) {
        return "<option value='" + key + "'>" + obj[key] + "</option>"           
    })}
    `;

我想为我的应用创建Google登录，但是我的结果代码onActivityResult()为0

在我的onCreate()方法中，我startSignInIntent()像这样启动函数：

protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        //some other stuff
        view.loadUrl(myURL);
        startSignInIntent();
}

这是 startSignInIntent()

private void startSignInIntent() {
        GoogleSignInClient signInClient = GoogleSignIn.getClient(this,
                GoogleSignInOptions.DEFAULT_SIGN_IN);
        Intent intent = signInClient.getSignInIntent();
        startActivityForResult(intent, RC_SIGN_IN);
    }

这是 onActivityResult()

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);
        Log.d(TAG, "data : " + resultCode + " | " + data  + " || " + RC_SIGN_IN + " ||| " + requestCode);
        if (requestCode == RC_SIGN_IN) …

我有一个概览页面，人们可以在其中查看结果。他们可以选择通过单击编辑按钮来更改该值。通过单击编辑按钮，您将导航到另一个页面，您可以在其中更改值。如果您更改了值，您将返回概览页面。但我的问题是我传递的道具this.$navigateBack()在概览页面中没有改变。

概览页面

<template>
<Page class="confirmPage" actionBarHidden="true">
    <StackLayout>
        <Button class="back fas btn btn-db" :text="'\uf060 Route Details' | unescape" @tap="$navigateBack"></Button>
        <GridLayout columns="2*, 2*, 1*" rows="*, *, *" class="routeDetails">
            <Label row="0" col="0" class="centerIt" text="Ziekenhuis"></Label>
            <Label row="0" col="1" :text="$props.hospital"></Label>
            <Label row="0" col="2" class="fas btn btn-t-d btn-cr-sm" :text="'\uf303' | unescape" @tap="onEditHospital"></Label>

            <Label row="1" col="0" class="centerIt" text="Startpunt"></Label>
            <Label row="1" col="1" :text="$props.startpoint"></Label>
            <Label row="1" col="2" class="fas btn btn-t-d btn-cr-sm" :text="'\uf303' | unescape" @tap="onEditStartpoint"></Label>

            <Label row="2" col="0" class="centerIt" text="Bestemming"></Label>
            <Label row="2" col="1" :text="$props.endpoint"></Label>
            <Label row="2" col="2" …

我在HTML页面中有一个href链接,我链接到这样的电子邮件地址:

<p>sometext <a href="mailto:mymailadresse@gmail.com">mymailadresse@gmail.com</a></p>

这是我的Android主要活动:

import android.app.Activity; 
import android.os.Bundle; 
import android.view.KeyEvent; 
import android.webkit.WebChromeClient; 
import android.webkit.WebView; 
import android.webkit.WebViewClient;

import com.google.android.gms.common.api.GoogleApiClient;

public class MainActivity extends Activity {

/**
 * ATTENTION: This was auto-generated to implement the App Indexing API.
 * See https://g.co/AppIndexing/AndroidStudio for more information.
 */
private GoogleApiClient client;
private WebView view;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    view = (WebView) this.findViewById(R.id.webView);
    view.getSettings().setJavaScriptEnabled(true);
    view.getSettings().setDomStorageEnabled(true);
    view.setWebViewClient(new MyBrowser());
    view.loadUrl("file:///android_asset/www/index.html"); //try js alert
    view.setWebChromeClient(new WebChromeClient()); // adding js alert 


}

/**
 * ATTENTION: …