小编mat*_*anm的帖子

使用 CocoaPods 在多个目标中引用 Firebase 时,构建运行但存档失败

我想在 Siri Intent 中使用 Firebase。我尝试运行它并且它可以工作,但是当我尝试归档该应用程序时,它无法归档。

我在 macOS Catalina 10.15.3 和 CocoaPods 1.8.4 上使用 Xcode 11.2.1。

错误是:

  • 多个命令产生'/Users/matan/Library/Developer/Xcode/DerivedData/Sendy-bqdzdmefsanhbvezkvawqizercwt/Build/Intermediates.noindex/ArchiveIntermediates/Sendy/IntermediateBuildFilesPath/UninstalledProducts/iphoneos/GTMSessionCore.framework':已创建带有输出'/Users/matan/Library/Developer/Xcode/DerivedData/Sendy-bqdzdmefsanhbvezkvawqizercwt/Build/Intermediates.noindex/ArchiveIntermediates/Sendy/IntermediateBuildFilesPath/UninstalledProducts/iphoneos/GTMworkSessionFetcher2Fetcher)的目录命令。 default-Core' 具有创建目录命令,输出为 '/Users/matan/Library/Developer/Xcode/DerivedData/Sendy-bqdzdmefsanhbvezkvawqizercwt/Build/Intermediates。noindex/ArchiveIntermediates/Sendy/IntermediateBuildFilesPath/UninstalledProducts/iphoneos/GTMSessionFetcher.framework'

  • 多个命令产生'/Users/matan/Library/Developer/Xcode/DerivedData/Sendy-bqdzdmefsanhbvezkvawqizercwt/Build/Intermediates.noindex/ArchiveIntermediates/Sendy/IntermediateBuildFilesPath/UninstalledProducts/iphoneos/GoogleUtilities.Targetwork':'5704GoogleUtilities.Targetwork':'5704Google已创建具有输出 '/Users/matan/Library/Developer/Xcode/DerivedData/Sendy-bqdzdmefsanhbvezkvawqizercwt/Build/Intermediates.noindex/ArchiveIntermediates/Sendy/IntermediateBuildFilesPath/UninstalledProducts/iphoneos/GoogleUtilities.framework' 的目录命令ac14cd06' 已创建目录命令,输出为 '/Users/matan/Library/Developer/Xcode/DerivedData/Sendy-bqdzdmefsanhbvezkvawqizercwt/Build/Intermediates。noindex/ArchiveIntermediates/Sendy/IntermediateBuildFilesPath/UninstalledProducts/iphoneos/GoogleUtilities.framework'

存档错误

播客文件:

project 'Sendy.xcodeproj'

# Uncomment the next line to define a global platform for your project
platform :ios, '13.0'

abstract_target 'SendyPods' do

  use_frameworks!

  pod 'Firebase/Core'
  pod 'Firebase/Auth'
  pod 'Firebase/Storage'
  pod 'Firebase/Firestore'
  pod 'FirebaseFirestoreSwift'

  target 'Sendy' do
    pod 'Firebase/Crashlytics'
    pod 'Firebase/Analytics'
    pod 'Firebase/Performance'
    pod 'FirebaseMessaging'
    pod 'GoogleSignIn'
  end

  target 'SendyIntents'

  target 'SendyIntentsUI'

end
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xcode ios cocoapods firebase swift

6
推荐指数
1
解决办法
773
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在 Swift 中使用参数创建流程?

在 Swift 3 中进行处理时出现问题,它不起作用,我单击并没有发生任何事情。

let open = Process()
open.launchPath = "/usr/bin/openssl"
open.arguments = ["openssl enc -aes-256-cbc -d -in \"" + existing.stringValue +
                 "\" -out \"" + new.stringValue + "/" + name.stringValue + "\""]
open.launch()
open.waitUntilExit()
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如何在 Swift 中创建带有参数的进程?

xcode command openssl process swift

1
推荐指数
1
解决办法
1464
查看次数

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