我用conditional_variable::notify_all()唤醒一个等待的线程（只有一个线程在等待unique_lock 确实）。
这个代码片段在大多数情况下都运行良好，但日志文件（详细信息见下文）表明unique_lock在新创建的线程已经返回后，父线程无法获取。
我将不胜感激能在这个问题上得到一些帮助。
这是相关的代码片段：
void MainWindow::deployAction(void)
{
std::condition_variable cvRunOver;
std::mutex mtxRunOver;
std::unique_lock <std::mutex> ulkRunOver(mtxRunOver);
QString workerThreadRes;
std::thread workThread([&]()
{
workThread.detach();
do_some_process_for_seconds();
cvRunOver.notify_all();
LOG(INFO)<<"to leave the subthread";
google::FlushLogFiles(google::GLOG_INFO);
return;
});
while (cvRunOver.wait_for(ulkRunOver, std::chrono::milliseconds(100)) == std::cv_status::timeout)
{
qApp->processEvents();
auto curTim = std::chrono::steady_clock::now();
std::chrono::duration<float> escapedTim= curTim-lastTim;
if(std::chrono::duration_cast<std::chrono::seconds>(escapedTim).count()>=5)
{
LOG(INFO) << "processEvents()";
google::FlushLogFiles(google::GLOG_INFO);
lastTim = curTim;
}
}
LOG(INFO) << "get lock and continue to run";
google::FlushLogFiles(google::GLOG_INFO);
}
以下是程序无法正常工作时的相关日志：
Log line format: [IWEF]hh:mm:ss.uuuuuu threadid file:line] …我正在尝试构建一个简单的示例，在 PyQt 窗口中显示 HTML（包括 JavaScript 代码）：
python
import sys
from PyQt5.QtWidgets import QWidget, QApplication, QVBoxLayout
from PyQt5.QtWidgets import QApplication
from PyQt5.QtCore import QUrl,QDir
from PyQt5.QtWebEngineWidgets import QWebEngineView
class Example(QWidget):
def __init__(self):
super().__init__()
vbox = QVBoxLayout(self)
self.webEngineView = QWebEngineView()
self.webEngineView.setHtml("""
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<script src="file:///home/path/to/jquery-3.6.0.min.js"></script>
</head>
<body>
<!-- page content -->
<span id="aaa">toto</span>
<script>
$("#aaa").hide()
</script>
</body>
</html>""")
vbox.addWidget(self.webEngineView)
self.setLayout(vbox)
self.show()
sys.argv.append("--disable-web-security")
app = QApplication(sys.argv)
ex = Example()
sys.exit(app.exec_())
但显然，位于我的 Python 脚本旁边的 jQuery JavaScript …
MWE 演示这个问题是这样的：
#include <QMainWindow>
#include <QApplication>
#include <QWidget>
#include <QWebEngineView>
#include <QGridLayout>
int main(int argc, char *argv[])
{
QApplication a(argc, argv);
QMainWindow w;
auto w1 = new QWidget();
w1->setLayout(new GridLayout());
auto view = new QWebEngineView();
view->load(QUrl("file://C:\\Users\\FruitfulApproach\\Desktop\\AbstractSpacecraft\\MathEnglishApp\\KaTeX_template.html"));
view->show();
w1->layout()->addWidget(view);
w.setCentralWidget(w1);
w.show();
return a.exec();
}
KaTeX_template.html：
<!DOCTYPE html>
<html>
<head>
<title>MathJax TeX Test Page</title>
<script type="text/x-mathjax-config">
MathJax.Hub.Config({tex2jax: {inlineMath: [['$','$'], ['\\(','\\)']]}});
</script>
<script type="text/javascript" async
src="https://example.com/mathjax/MathJax.js?config=TeX-AMS_CHTML">
</script>
</head>
<body>
When $a \ne 0$, there are two solutions to \(ax^2 + bx + c …谁能告诉我如何将命令的输出设置为变量？
基本上，我正在寻找与此bash示例等效的Python：
blah="ajsdlk akajl <ajksd@ajksldf.com>"
blah=$(echo "$blah" | cut -d '<' -f 2 | cut -d '>' -f 1)
echo "$blah"
ajksd@ajksldf.com
class Strength(State):
def run(self, gamedata):
print("You have 100 points to assign to your character.\n Start now to assign those Points to your characters strength, agility, speed and defense.")
strenghtwert = int(input("STRENGTH: >>"))
return AGILITY, gamedata, strenghtwert
def next(self, next_state):
if next_state == AGILITY:
return CreatePlayer.agility
class Agility(State):
def run(self, gamedata,strenghtwert):
agilitywert = int(input("AGILITY: >>"))
return SPEED, gamedata, strenghtwert, agilitywert
def next(self, next_state):
if next_state == SPEED:
return CreatePlayer.speed
执行此操作时，出现错误：ValueError: too many values to unpack (expected 2)。我认为错误是return AGILITY, …
我有超过 10 个复选框。
我需要按用户创建一个选中的复选框列表，因为每个复选框都有自己的功能，该功能取决于选中的复选框的数量！
LRESULT CALLBACK MouseProc(int nCode, WPARAM wParam, LPARAM lParam)
{
if (nCode == HC_ACTION)
{
if (wParam == WM_MOUSEMOVE)
{
cout << "X : " << GET_X_LPARAM(lParam) << " Y: " << GET_Y_LPARAM(lParam) << "\n";
}
}
return CallNextHookEx(hMSHook, nCode, wParam, lParam);
}
int _tmain() {
HMODULE hInstance = GetModuleHandle(NULL);
hMSHook = SetWindowsHookEx(WH_MOUSE_LL, MouseProc, hInstance, NULL);
MSG Msg;
while (GetMessage(&Msg, NULL, 0, 0)) { DispatchMessage(&Msg); }
::ReleaseDC(0, dc);
return 0;
}
结果 = 总是返回错误的坐标，
示例 = X = -1844，Y = 79， …
我试图一步一步地了解这个程序是如何工作的
for n in range(2, 10):
for x in range(2, n):
if n % x == 0:
print(n, 'equals', x, '*', n//x)
break
else:
# loop fell through without finding a factor
print(n, 'is a prime number')
for i in range(2,2):
print(i)
这段代码不打印任何内容，那么我包含的实际值是什么，它是否包含垃圾值。
Split() function uses whitespace string as separator and removes the empty strings, so I think there is no use using strip() or rstrip() function to remove extra whitespace in head or tail. And here is my example:
a = ' \n 1 2 3 4 \n\n 5 \n\n \t'
b = a.rstrip().split()
c = a.split()
print('b =',b)
print('c =',c)
The result turns out to be:
b = ['1', '2', '3', '4', '5']
c = ['1', '2', '3', '4', '5']
It …
实际上我可以使用Go语言中的两个循环来完成它,例如,如果我有数组:
["aa", "aab", "bcd", "a", "cdf", "bb"]
我需要使用maxLength返回字符串.所以输出将是:
["aab", "bcd", "cdf"]
这就是我在做什么.
package main
import "fmt"
func allLongestStrings(inputArray []string) []string {
maxLength := len(inputArray[0])
outputArray := []string{}
for _, value := range inputArray {
if len(value) > maxLength {
maxLength = len(value)
}
}
for _, val := range inputArray {
if len(val) == maxLength {
outputArray = append(outputArray, val)
}
}
return outputArray
}
func main() {
xs := []string{"aa", "aab", "bcd", "a", "cdf", "bb"}
fmt.Println(allLongestStrings(xs))
}
是否可以在一个循环中执行此操作,因为我运行相同的循环两次以查找长度并在outputArray中追加字符串.
提前致谢.
python ×6
c++ ×3
python-3.x ×3
pyqt ×2
qt ×2
c++11 ×1
hook ×1
mousemove ×1
pycharm ×1
pyqt5 ×1
qtwebengine ×1
split ×1
strip ×1
unique-lock ×1
winapi ×1