ValueError：太多值无法解包（预期2）PYTHON

Question

class Strength(State):
    def run(self, gamedata):
        print("You have 100 points to assign to your character.\n Start now to assign those Points to your characters strength, agility, speed and defense.")
        strenghtwert = int(input("STRENGTH: >>"))
        return AGILITY, gamedata, strenghtwert

    def next(self, next_state):
        if next_state == AGILITY:
            return CreatePlayer.agility

class Agility(State):
    def run(self, gamedata,strenghtwert):
        agilitywert = int(input("AGILITY: >>"))
        return SPEED, gamedata, strenghtwert, agilitywert

    def next(self, next_state):
        if next_state == SPEED:
            return CreatePlayer.speed

执行此操作时，出现错误：ValueError: too many values to unpack (expected 2)。我认为错误是return AGILITY, gamedata, strenghtwert在run()班上Strength。

知道有什么问题吗？

成功执行的最后一行strenghtwert = int(input("STRENGTH: >>"))在同一函数中。

Answer 1

如果没有更多信息，例如如何进行调用，这些变量的类型是什么，错误的堆栈跟踪或完整的代码。

多次分配期间通常会发生此错误，在这种情况下，您没有足够的对象分配给变量，或者您分配的对象比变量多。

例如，如果myfunction（）返回的迭代器包含三个项目，而不是预期的两个项目，那么您将拥有比分配给变量所需的对象更多的对象。

def myfunction():
    return 'stuff', 'and', 'junk'

stuff, junk = myfunction()

Traceback (most recent call last): File "/test.py", line 72, in <module> stuff, junk = myfunction() ValueError: too many values to unpack (expected 2)

这可以在变量多于对象的地方以另一种方式起作用。

def myfunction():
    return 'stuff'

stuff, junk = myfunction()

Traceback (most recent call last): File "/test.py", line 72, in <module> stuff, junk = myfunction() ValueError: too many values to unpack (expected 2)