小编une*_*eer的帖子

中心对齐水平位置绝对对象

我有一个元素,其位置是绝对的,我面临的唯一问题是我已经应用了一些属性来水平居中对齐,它在mozilla上工作正常,但相同的属性不适用于chrome这里是我的代码

HTML

<a href="#section1" class="scrollTo downarrow"><img src="images/navbar_downarrow.png" class="img-responsive"/></a>
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CSS

    .slider{
        position: relative;
        background-image: url("../images/slider.jpg");
        background-size: 100% 100%;
        background-repeat: no-repeat;
    }
    .slider a.downarrow{
        position: absolute;
        margin-left: auto;
        margin-right: auto;
        left: 0;
        right: 0;
        bottom: 20px;
        display: table;
    }
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css

10
推荐指数
1
解决办法
1万
查看次数

用导航栏绘制一条小垂直线

我需要绘制一条小垂直线,它应该出现在每个导航栏li之后.

问题是每当我尝试绘制一些东西时,导航栏就会搞砸,导航栏会进入第二行.我不能画一条垂直线.这是代码

HTML

<!DOCTYPE HTML>
<html>
<head>

    <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
    <meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1">
    <title>Double Double</title>
    <link rel="shortcut icon"  href="favicon.ico">
    <link href='http://fonts.googleapis.com/css?family=Roboto:400,100,300,500,700%7CRoboto+Slab:400,100' rel='stylesheet' type='text/css' />
    <link href="css/font-awesome.min.css" rel="stylesheet">
    <link href="css/bootstrap.min.css" rel="stylesheet">
    <link href="css/double.css" rel="stylesheet">
</head>

<body>
<nav class="navbar" role="navigation">
    <div class="container">
        <!-- Brand and toggle get grouped for better mobile display -->
        <div style="margin: auto;display: table;">
            <div class="navbar-header">
                <button type="button" class="navbar-toggle" data-toggle="collapse" data-target="#bs-example-navbar-collapse-1">
                    <span class="sr-only">Toggle navigation</span>
                    <span class="icon-bar"></span>
                    <span class="icon-bar"></span>
                    <span class="icon-bar"></span>
                </button>
            </div>

            <!-- …
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css twitter-bootstrap

4
推荐指数
1
解决办法
1万
查看次数

从 cellrenderer 调用父函数,例如在 vuejs ag-grid-vue 上发出

我已经在我的项目上实现了,ag-grid-vue现在我在其中一列上有一个单独的组件,基本上是Actions,现在用户可以根据选择编辑视图或删除,现在编辑和删除它工作得很好,问题是当我删除记录时,我希望通过从 Api 获取更新的数据来重新呈现表格,为此我需要从 CellRenderer 组件调用父级中的某些方法,让我向您展示代码

超文本标记语言

<ag-grid-vue
        ref="agGridTable"
        :components="components"
        :gridOptions="gridOptions"
        class="ag-theme-material w-100 my-4 ag-grid-table"
        :columnDefs="columnDefs"
        :defaultColDef="defaultColDef"
        :rowData="accounts"
        rowSelection="multiple"
        colResizeDefault="shift"
        :animateRows="true"
        :floatingFilter="true"
        :pagination="true"
        :paginationPageSize="paginationPageSize"
        :suppressPaginationPanel="true"
        :enableRtl="$vs.rtl">
      </ag-grid-vue>
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JS

import CellRendererActions from "./CellRendererActions.vue"

  components: {
    AgGridVue,
    vSelect,
    CellRendererActions,
  },

columnDefs: [
{
          headerName: 'Account ID',
          field: '0',
          filter: true,
          width: 225,
          pinned: 'left'
        },{
          headerName: 'Account Name',
          field: '1',
          width: 250,
          filter: true,
        },
         {
          headerName: 'Upcoming Renewal Date',
          field: '2',
          filter: true,
          width: 250,
        }, …
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javascript vue.js ag-grid vuejs2 ag-grid-vue

4
推荐指数
1
解决办法
3584
查看次数

如何打破一行java脚本

我正在通过java脚本设置h4的文本我想要做的是在这里添加新行代码

$("#description").text("for CCAET and has received significant international scientific recognition. <br /> \n Dr. Armogan has also been responsible for many surgical firsts in retina and cataract management.");
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现在我尝试了多种解决方案,但仍然没有在这里工作的另一个

$("#description").text("or CCAET and has received significant international scientific recognition.Dr. Armogan has also been responsible for many surgical firsts in retina and cataract management."+
                        "abc"+
                         "def");
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任何帮助?

javascript jquery

1
推荐指数
1
解决办法
76
查看次数

试图在json_decode中获取非对象的属性

我是JSON的新手,我有一个以数据库形式从数据库中检索到的json对象

Array
(
    [0] => stdClass Object
        (
            [id] => 1
            [data] => {"vehicle":[{"year":"2000","make":"Ac","model":"Aceca","acquired_year":"2016","acquired_month":"2","use":"Business","distance_driven_to_work_or_school":"2","distance_driven_manually":"10000"}],"first_name":"ADAS","last_name":"DSADSADA","email":"asddsa@sda.com","phone":"dsasasa","postal_code":"","drivers":[{"name":"ssada","birth_year":"2016","birth_month":"2","birth_day":"2","gender":"female","martial_status":"Single","license_number_provided":"yes","license_number":"asddasdas","license_type":"","training_completed":"","years_been_listed_on_auto_policy_in_north_america":"No Previous Experience","license_suspensions":"","accidents":"Select","convictions":"Select","cancellation_reason":"","cancellation_year":"","cancellation_month":"","cancellation_day":""}],"considering_renters_to_reduce_rate":"yes","install_winter_tires":"no","park_in_private_driveway":"yes","willing_to_install_device":"no","years_insured_with_current_company":"4 Years","how_heard_about_us":"asdaa"}
            [date] => 2017-11-20 18:17:52
            [status] => 0
        )

)
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现在,当我尝试使用json_decode将其转换为数组时,我正在尝试获取非对象的属性这里是我的代码

<?php
    echo "<pre>";
    print_r($quotes);  //works fine uptil here
    $data = json_decode($quotes->data,true);//the error line
    echo "<pre>";
    print_r($data);
?>
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我尝试了几种方法,但它没有工作我尝试了一些其他的解决方案,以及最终得到错误任何帮助?

php json

0
推荐指数
1
解决办法
2496
查看次数

如果在十进制之后有一个零,则添加一个零

我有定价格式,其中有许多场景我必须处理!

我的基本要求是在小数点后必须有两个值,例如

20.20
100.03
30.34
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等等,现在我收到的定价类型是

30.3
25.52 
100.02
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等等

现在我要构建的逻辑是,如果小数点后面有两个值,它应该按原样显示它们,不做任何改动.但是如果在小数点之后有一个值,例如30.3它应该添加一个尾随零但只有两位数!这就是我现在拥有的!

  <h6> <?php $starting_from = explode('.',$result_1s['price']) ?>
  $<?=round($starting_from[0])?><?=(is_numeric($result_1s['price']) && floor($result_1s['price']) != $result_1s['price']) ? '.'.$starting_from[1] :'.00' ?>
 </h6>
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如何修改上面的代码,它接受我上面解释的场景.提前致谢!

php

-1
推荐指数
1
解决办法
37
查看次数