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如何在Spark SQL中从列表创建数据框?

Spark版本:2.1

例如,在pyspark中,我创建一个列表

test_list = [['Hello', 'world'], ['I', 'am', 'fine']]

那么如何从test_list创建一个数据框,其中数据框的类型如下所示:

DataFrame[words: array<string>]

python apache-spark pyspark

16
推荐指数
3
解决办法
4万
查看次数

当我使用sbt构建spark自包含应用程序时,编译失败

我试图通过使用sbt来构建并发症.

代码:https://github.com/apache/spark/blob/master/examples/src/main/scala/org/apache/spark/examples/ml/ALSExample.scala

教程:http://spark.apache.org/docs/latest/quick-start.html#self-contained-applications

但错误发生了.

[error] /home/zeng/workspace/spark/als/src/main/scala/ALSExample.scala:22:object ml is not a member of package org.apache.spark
[error] import org.apache.spark.ml.evaluation.RegressionEvaluator
[error]                         ^
[error] /home/zeng/workspace/spark/als/src/main/scala/ALSExample.scala:23: object ml is not a member of package org.apache.spark
[error] import org.apache.spark.ml.recommendation.ALS
[error]                         ^
[error] /home/zeng/workspace/spark/als/src/main/scala/ALSExample.scala:25: object sql is not a member of package org.apache.spark
[error] import org.apache.spark.sql.SparkSession
[error]                         ^
[error] /home/zeng/workspace/spark/als/src/main/scala/ALSExample.scala:46: not found: value SparkSession
[error]     val spark = SparkSession
[error]                 ^
[error] /home/zeng/workspace/spark/als/src/main/scala/ALSExample.scala:61: not found: type ALS
[error]     val als = …
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sbt apache-spark

0
推荐指数
1
解决办法
1477
查看次数

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