小编Moh*_*q P的帖子

Intellij的想法说Java Home是不同的

新创建的守护进程具有与预期不同的上下文.无法重新连接到此守护程序.上下文不匹配:
Java home不同.

求购:DefaultDaemonContext [UID = NULL,JAVAHOME = /家庭/管理者/下载/ IDEA-IU-145.1617.8/JRE,daemonRegistryDir = /家庭/管理者/ .gradle /守护进程,PID = 11963,的idleTimeout = NULL,daemonOpts = - XX:MaxPermSize参数= 256M,-XX:+ HeapDumpOnOutOfMemoryError,-Xmx1024m,-Dfile.encoding = UTF-8,-Duser.country = IN,-Duser.language = EN,-Duser.variant]

实际:DefaultDaemonContext [uid = 4839fb8c-418b-4666-9a66-40a60133958a,javaHome =/usr/lib/jvm/java-8-openjdk-amd64,daemonRegistryDir =/home/administrator/.gradle/daemon,pid = 15202,idleTimeout = 60000,daemonOpts = -XX:MaxPermSize参数= 256M,-XX:+ HeapDumpOnOutOfMemoryError,-Xmx1024m,-Dfile.encoding = UTF-8,-Duser.country = IN,-Duser.language = EN,-Duser.variant]

intellij-idea gradle

27
推荐指数
2
解决办法
2万
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如何在 Angular 中为反应形式构建可重用字段

我正在尝试为反应式表单构建一个可重用的字段组件,但我无法从custom-input组件中获取值。

<form [formGroup]="form" (ngSubmit)="submit()">
  <custom-input id="name" name="name" formControlName="name"></custom-input>
  <button type="submit" name="button">Submit</button>
</form>
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我的自定义输入可重用组件

import { Component, OnInit, Input } from '@angular/core';
import { FormControl } from "@angular/forms";

@Component({
  selector: 'custom-input',
  template: '<input type="text" [class]="class" [id]="id" [name]="name" [formControlName]="formControlName">',
  styles: []
})
export class CustomInputComponent implements OnInit {
  @Input() public id: string;
  @Input() public class: string;
  @Input() public name: string;
  @Input() public formControlName: string;

  constructor() { }

  ngOnInit() {
  }
}
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javascript angular2-forms angular

3
推荐指数
1
解决办法
3269
查看次数