小编Brn*_*rns的帖子

使用名称创建 bean 时出错

我正在创建一个基于 Spring MVC Maven 模块的项目,因此我将每一层划分为一个 Maven 模块。当我尝试运行基本站点时,代码可以正常编译,但出现错误:

SEVERE: Context initialization failed
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'addressController' defined in file [C:\Program Files\Apache Software Foundation\Tomcat 8.0\wtpwebapps\croz-web\WEB-INF\classes\hr\croz\bspoljaric\controller\AddressController.class]: Post-processing of merged bean definition failed; nested exception is java.lang.IllegalStateException: Failed to introspect bean class [hr.croz.bspoljaric.controller.AddressController] for resource metadata: could not find class that it depends on
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:525)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:483)
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:306)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:230)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:302)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:197)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:759)
at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:866)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:542)
at org.springframework.web.context.ContextLoader.configureAndRefreshWebApplicationContext(ContextLoader.java:403)
at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:306)
at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:106)
at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:4851)
at …
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java spring spring-mvc maven

2
推荐指数
1
解决办法
2万
查看次数

将代码转换为lambda

我正在尝试将我的"长"代码转换为更简单的lambda驱动代码.想法是从枚举中获取价值.如果第一个值更高或更低,则将其返回并将lambda从进一步打破.我不知道从哪里开始.Lambda从枚举中返回代码,它可以很好地计算差异.我的问题是,一旦发现差异,就会获得返回和/或破坏lambda的值.

代码不起作用:

BiFunction<Map<String, Integer>,Map<String, Integer>,Integer> biFunction = (m1, m2) -> {
    enumWords.forEach(word -> {
        Integer returnValue = 0;
        if(m1.get(word) > m2.get(word)){
            returnValue = m1.get(word).compareTo(m2.get(word));
            break;
        }
    });
    return returnValue;     
};
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这是有效的代码(pre-lambda):

BiFunction<Map<String, Integer>,Map<String, Integer>,Integer> biFunction = (m1, m2) -> {
            Integer returnValue = 0;
            if(m1.get("Love") > m2.get("Love")){
                returnValue = -1;
            }else if(m1.get("Love") < m2.get("Love")){
                returnValue = 1;
            }else{
                if(m1.get("You") > m2.get("You")){
                    returnValue = -1;
                }else if(m1.get("You") < m2.get("You")){
                    returnValue = 1;
                }else{
                    if(m1.get("Me") > m2.get("Me")){
                        returnValue = -1;
                    }else if(m1.get("Me") …
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java lambda java-8

1
推荐指数
1
解决办法
105
查看次数

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