小编Anc*_*rya的帖子

I am using multipledispatch to make a Point class, which has three constructors: one that takes a single integer, one that takes two, and one that takes an object of type Point. But I am unable to implement the third constructor as I don't know what argument to give to the @dispatch decorator, since the class Point is not yet defined. I have currently resorted to using object, but is there any way I can use Point itself?

Here's …

我在kotlin 文档中找到了这段代码：

var stringRepresentation: String
get() = this.toString()
set(value) {
    setDataFromString(value) // parses the string and assigns values to other properties
}

我不明白this.toString()这里有什么。this指整个对象。为什么每次访问对象时都希望将其转换为字符串？真的应该这样field.toString()吗？（但这也是多余的）

我通常将2D数组（按值）传递给函数“ elem”，然后将其进一步传递给另一个函数“ interchange”，该函数执行行交换操作并显示它。但是问题是，在我从交换返回到main（）之后，数组的值已从交换更改为结果数组，即使从技术上讲它们对于三个不同的函数（main，elem和interchange）必须是三个不同的变量）。为什么会这样，我该怎么做才能使main（）中的数组保持不变？

//include files... 

void interchange(float c[10][10],int m,int n)
{
    int i,j,p,q;
    float temp;

        printf("\nEnter the two row numbers to interchange:");
        scanf("%d%d",&p,&q);

        if((--p<m)&&(--q<n))
        {
            for(i=0;i<m;i++)
            {
                temp=c[p][i];
                c[p][i]=c[q][i];
                c[q][i]=temp;
            }
        } else
        {
            printf("Row numbers must be less than matrix order.\n");
            return;
        }

    printf("\nResultant matrix is:\n"); //print the array in interchange,c
    printf("\n");
    for(i=0;i<m;i++)
        {for(j=0;j<n;j++)
            {
                printf("%f\t",c[i][j]); 
            }
         printf("\n");
        }
}

void elem(float b[10][10],int m,int n)
{
    int ch;
    do
    {
        printf("\n1:Row interchange\t 2:Exit elementary transformations\n\nEnter the choice:");
        scanf("%d",&ch);  //get …