已解决(见下文)

当我试图在我的Ruby on Rails应用程序(或在控制台中)创建或销毁记录(在SQLite3上运行)时,我得到一个SQL异常:

irb(main):014:0> ApiCache.all
=> []
irb(main):015:0> ApiCache.create(:hash => 'qwe', :contents => 'asd')
SQLite3::SQLException: cannot rollback - no transaction is active
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/sqlite3-1.3.3-x86-mingw32/lib/sqlite
3/database.rb:97:in `close'
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/sqlite3-1.3.3-x86-mingw32/lib/sqlite
3/database.rb:97:in `prepare'
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/sqlite3-1.3.3-x86-mingw32/lib/sqlite
3/database.rb:134:in `execute'
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/sqlite3-1.3.3-x86-mingw32/lib/sqlite
3/database.rb:517:in `rollback'
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/activerecord-3.0.6/lib/active_record
/connection_adapters/sqlite_adapter.rb:168:in `rollback_db_transaction'
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/activerecord-3.0.6/lib/active_record
/connection_adapters/abstract/database_statements.rb:176:in `transaction'
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/activerecord-3.0.6/lib/active_record
/transactions.rb:207:in `transaction'
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/activerecord-3.0.6/lib/active_record
/transactions.rb:290:in `with_transaction_returning_status'
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/activerecord-3.0.6/lib/active_record
/transactions.rb:240:in `save'
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/activerecord-3.0.6/lib/active_record
/transactions.rb:251:in `rollback_active_record_state!'
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/activerecord-3.0.6/lib/active_record
/transactions.rb:239:in `save'
        from C:/RailsInstaller/Ruby1.8.7/lib/ruby/gems/1.8/gems/activerecord-3.0.6/lib/active_record
/base.rb:498:in `create'
        from (irb):15
        from :0
irb(main):016:0> ApiCache.all
=> [#<ApiCache id: …

我需要使用我的PHP脚本从远程服务器下载文件.问题是我收到的链接看起来像" example.com?download=12345 ".所以我想用正确的扩展名保存文件,并且(最好)保留它的原始文件名.我该怎么做呢？谢谢你们!