我的应用程序是这样的,如果它抛出异常,我希望驱动程序关闭,我尝试了以下代码,但它抛出异常。
我的代码:其中 url 是我要打开的网址
driver=webdriver.Firefox()
try:
driver.get(url)
except:
driver.quit()
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它正在关闭驱动程序但抛出异常。我应该如何解决这个问题?
这是我的堆栈跟踪
raceback (most recent call last):
File "/folderpath", line 47, in <module>
driver.close()
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 505, in close
self.execute(Command.CLOSE)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/webdriver.py", line 231, in execute
response = self.command_executor.execute(driver_command, params)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/remote_connection.py", line 395, in execute
return self._request(command_info[0], url, body=data)
File "/usr/local/lib/python2.7/dist-packages/selenium/webdriver/remote/remote_connection.py", line 425, in _request
self._conn.request(method, parsed_url.path, body, headers)
File "/usr/lib/python2.7/httplib.py", line 973, in request
self._send_request(method, url, body, headers)
File "/usr/lib/python2.7/httplib.py", line 1007, in _send_request
self.endheaders(body)
File "/usr/lib/python2.7/httplib.py", line …Run Code Online (Sandbox Code Playgroud)