小编Jer*_*son的帖子

仅返回基于另一个变量的第一个实例

我有一个ID列表(有些是重复的),我有一个KEEP变量.如果在KEEP列中有这样的实例,我想创建一个1或0的列,即使它不是那个特定的列

id <- c(101,101,101,102,102,102,103,103,103,104,104,106,107,108)
keep <- c("Y",0,0,"Y",0 ,0 ,"Y" ,0 ,0 ,0 ,0 ,0 ,0 ,0)
df <- data.frame(id, keep)
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我想创建第三列,如果保留列中有一个Y,则匹配所有ID.

看起来应该是这样的.

> df

    id keep countkeep
1  101    Y         1
2  101    0         1
3  101    0         1
4  102    Y         1
5  102    0         1
6  102    0         1
7  103    Y         1
8  103    0         1
9  103    0         1
10 104    0         0
11 104    0         0
12 106    0         0
13 107    0 …
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r

2
推荐指数
1
解决办法
113
查看次数

从 R 中的字符串中删除美元符号和逗号

从我见过的所有答案来看,这似乎是其他语言中的常见问题,但我在 R 数据框中遇到了这个问题。我有用美元符号和逗号导入的数据,但我似乎无法将它们取出。我已经尝试了所有我能想到的 str_sub 类型的东西,但无法将它们取出。看起来他们只是被忽视了。

test.df <- structure(list(week_ending = structure(c(18747, 18747, 18747,18747, 18747, 18747, 18747, 18747, 18747, 18747), class = "Date"),store_num = c(7005, 7005, 7005, 7005, 7005, 7005, 7005, 7748,7748, NA), units = c("116", "1", "6", "2", "1", "1", "2","1", "46", "2,539"), cost = c("$699.36", "$14.29", "$34.02","$0.90", "$11.47", "$1.28", "$2.16", "$1.89", "$165.81","$16,250.83 "), dollars = c("$1,564.07 ", "$24.99", "$54.00","$9.98", "$24.99", "$2.99", "$7.98", "$4.99", "$360.11","$37,465.88 "), item_description = c("$1,564.07 ", "$24.99","$54.00", "$9.98", "$24.99", "$2.99", "$7.98", "$4.99", "$360.11","$37,465.88 ")), row.names = c(1L, …

string r

2
推荐指数
1
解决办法
1736
查看次数

将R Vector传递给Sql查询

我正在使用RODBC包访问我在R中的sql数据库.我无法找到有关如何将矢量从R传递到sql作为向量的任何有用信息.

    id <- ('00003', '00100')
    query <- sqlQuery(channel = channel, query = "select *
                  from prod_cust_vw.store_dim
                  where store_num in id")
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我想将id向量传递给sql而不是硬编码.

sql r rodbc

1
推荐指数
2
解决办法
3043
查看次数

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r ×3

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