我有一个数据框,按日期的降序排列.
ps1 = data.frame(userID = c(21,21,21,22,22,22,23,23,23),
color = c(NA,'blue','red','blue',NA,NA,'red',NA,'gold'),
age = c('3yrs','2yrs',NA,NA,'3yrs',NA,NA,'4yrs',NA),
gender = c('F',NA,'M',NA,NA,'F','F',NA,'F')
)
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我希望将NA值用先前的值归入(替换)并按userID分组如果userID的第一行有NA,则替换为该用户ID组的下一组值.
我正在尝试使用像这样的dplyr和zoo软件包......但它不起作用
cleanedFUG <- filteredUserGroup %>%
group_by(UserID) %>%
mutate(Age1 = na.locf(Age),
Color1 = na.locf(Color),
Gender1 = na.locf(Gender) )
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我需要结果df像这样:
userID color age gender
1 21 blue 3yrs F
2 21 blue 2yrs F
3 21 red 2yrs M
4 22 blue 3yrs F
5 22 blue 3yrs F
6 22 blue 3yrs F
7 23 red 4yrs F
8 23 red 4yrs F
9 …Run Code Online (Sandbox Code Playgroud) 我有一个keras模型(使用R)和TF作为后端,如下
history <- model %>% fit( train_X1,train_y,batch_size=100,
epochs=80,validation_split = 0.2,
shuffle=TRUE)
> class(model)
[1] "keras.models.Sequential" "keras.engine.training.Model"
[3] "keras.engine.topology.Container" "keras.engine.topology.Layer"
[5] "python.builtin.object"
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尺寸如下:
> dim(train_X1)
[1] 4893 64 64 1
> dim(train_y)
[1] 4893 12
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我想先在火车上评估,然后在测试中预测。
model %>% evaluate(train_X1,train_y)
pred <- model %>% predict_classes(train_X1)
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但是在运行评估命令时出现以下错误:
Error in do.call(object$evaluate, args) : 'what' must be a function or character string
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任何帮助将不胜感激。谢谢
我有两个数据框:
as1 <- data.frame(ID = c(1,2,3,4,5,6),
pID = c(21,22,23,24,25,26),
Values = c(435,33,45,NA, NA,12))
as2 <- data.frame(ID = c(4,5),
pid = c(24,25),
Values = c(544, 676))
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我需要通过匹配ID和pID将as1中的NA值替换为as2中的NA值
我需要获取结果数据框架为:
resultdf
ID pID Values
1 1 21 435
2 2 22 33
3 3 23 45
4 4 24 544
5 5 25 676
6 6 26 12
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我尝试先做子集,然后na.omit()再执行rbind...但是我丢失了索引。
我有一个数据帧.我希望检测连续数字并将新列填充为1或0.
ID Val
1 a 8
2 a 7
3 a 5
4 a 4
5 a 3
6 a 1
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预期产出
ID Val outP
1 a 8 0
2 a 7 1
3 a 5 0
4 a 4 1
5 a 3 1
6 a 1 0
Run Code Online (Sandbox Code Playgroud) 我有一个数据框str是
'data.frame': 334 obs. of 6 variables:
$ Patient_ID : int 524451 517060 518025 515768 499994
$ Camp_Start_Date : Date, format: "2003-08-16" "2005-02-15" "2005-02-15" ...
$ Camp_End_Date : Date, format: "2003-08-20" "2005-02-18" "2005-02-18" ...
$ First_Interaction: Date, format: "2003-08-16" "2004-10-03" "2005-02-17" ...
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我用它来创建一个新的列pRegDate
RegDatelogicLUT <- RegDatelogicLUT %>%
mutate(pRegDate = if_else(between(First_Interaction, Camp_Start_Date, Camp_End_Date), First_Interaction, Camp_Start_Date)
)
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得到错误。
Error: expecting a single value
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任何帮助将不胜感激。谢谢
我有一个输入文字
inputQ <- "What can I do ..my baby has rash all over. Suggest good rash cream"
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我有一份条款清单
terms <- c("diaper","cloth diaper","rash pants","rash","baby wipes","rash cream")
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我希望完全匹配其中一个术语并返回它我尝试使用for循环,但是有更好的方法
结果应该是
rash cream
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存储在matchedTerm中