小编kez*_*iah的帖子

成功购买后,PHP Stripe获取交易ID

我试图在购买后获取交易ID,但它在谢谢页面上返回空

order.php

<?php
\Stripe\Stripe::setApiKey('<test token>');

$amount = 100;
$card = $_POST['stripeToken'];

// Create a Customer
$customer = \Stripe\Customer::create(array(
    "source" => $card,
    "email" => $email,
    "description" => "Example description")
);

// Charge the Customer instead of the card
$charge = \Stripe\Charge::create(array(
    "amount" => 100,
    "currency" => "usd",
    "customer" => $customer->id)
);

// Save the billing info
set_billing([
    'customer_id' => $customer->id,
    'address' => $address,
    'address2' => $address2,
    'city' => $city,
    'state' => $state,
    'country' => $country,
    'postal' => $postal,
    'trans_id' => $charge->id …
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php payment stripe-payments

1
推荐指数
1
解决办法
7502
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PHP mysqli只显示一个用户

我想实现这一目标

  • 约翰 - >子用户
  • 约翰 - >子用户
  • mark - > sub user
  • mark - > sub user
  • 戴夫 - >子用户
  • 戴夫 - >子用户

但这是意料之外的输出

  • 约翰 - >子用户
  • 约翰 - >子用户

只有用户名john已经出现

// Get all the users
$s = $sqlConnection->query('SELECT * FROM accounts');

while ($row = $s->fetch_assoc())
{
    $uarr = explode(',', $row['username']);

    foreach ($uarr as $ueach)
    {        
        // Get all the direct sales
        $query = "SELECT *";
        $query .= " FROM accounts ACC";
        $query .= " INNER JOIN info …
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php mysql arrays mysqli loops

0
推荐指数
1
解决办法
112
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php ×2

arrays ×1

loops ×1

mysql ×1

mysqli ×1

payment ×1

stripe-payments ×1