<html>
<head>
<style>
table,td {border:1px solid black ;}
table {width : 80% ;height:80%;}
.top {vertical-align:top};
.center {vertical-align: middle};
.bottom {vertical-align: bottom};
</style>
</head>
<body>
<table>
<tbody>
<tr><td class = "top">1</td><td class = "top" "left">2</td><td class = "top" "left">3</td></tr>
<tr><td class = "center" >4</td><td class = "center">5</td><td class = "center">6</td></tr>
<tr><td class = "bottom">7</td><td class = "bottom">8</td><td class = "bottom">9</td></tr>
</tbody>
</table>
</body>
</html>
8号线即可.bottom {vertical-align: bottom};在互联网浏览器8中完美运行,但即使我拥有最新版本,它也不适用于谷歌浏览器.
我已经全部成立了.我已经安装了android sdk api 24和所有必要的工具.我也尝试重新安装离子和cordova,但它不起作用.
这是错误日志:
D:\Coursera\Course 4\myapp1\public>ionic platform add android
Adding android project...
Creating Cordova project for the Android platform:
Path: platforms\android
Package: com.ionicframework.myapp1409522
Name: myapp1
Activity: MainActivity
Android target: android-24
Subproject Path: CordovaLib
Android project created with cordova-android@6.0.0
Installing "cordova-plugin-console" for android
Failed to install 'cordova-plugin-console':Error: cmd: Command failed with exit
code ENOENT
at ChildProcess.whenDone (C:\Users\Sahib\AppData\Roaming\npm\node_modules\co
rdova\node_modules\cordova-common\src\superspawn.js:169:23)
at emitOne (events.js:96:13)
at ChildProcess.emit (events.js:188:7)
at Process.ChildProcess._handle.onexit (internal/child_process.js:213:12)
at onErrorNT (internal/child_process.js:359:16)
at _combinedTickCallback (internal/process/next_tick.js:74:11)
at process._tickCallback (internal/process/next_tick.js:98:9)
Error: cmd: Command failed …我在C中创建了一个非常简单的链表列表程序.
#include<stdio.h>
#include<stdlib.h>
int main(){
struct Int{
int num;
struct Int *ptr;
};
typedef struct Int NODE;
NODE *start;
start = (NODE *) malloc(sizeof(NODE));
(*start).num = 100;
(*start).ptr = (NODE *) malloc(sizeof(NODE));
(*start).(*ptr).num = 123;
(*start).(*ptr).ptr = NULL;
}
当我将最后两行替换为: -
start -> ptr -> num = 123;
start -> ptr -> ptr = NULL;
错误解决了.
问题是为什么我不能用(* start).而不是.start ->根据这个答案这是什么意思" - >"？
两者都是一样的.