小编Ben*_*eiß的帖子

当我编写一个返回对局部变量的引用的函数时,GCC会生成错误的指令.我完全知道你不应该这样做.

这是简单的代码:

#include <stdio.h>
#include <stdlib.h>

int *func()
{
    int a = 100;
    return &a;
}

int main()
{
    printf("%p\n", func());
}

程序的输出是"(零)".

我刚用"gcc sample.c"编译了这个,并用gdb反汇编了可执行文件:

Dump of assembler code for function func:
   0x00000000004004e6 <+0>: push   %rbp
   0x00000000004004e7 <+1>: mov    %rsp,%rbp
   0x00000000004004ea <+4>: movl   $0x64,-0x4(%rbp)
   0x00000000004004f1 <+11>:    mov    $0x0,%eax
   0x00000000004004f6 <+16>:    pop    %rbp
   0x00000000004004f7 <+17>:    retq   
End of assembler dump.
Dump of assembler code for function main:
   0x00000000004004f8 <+0>: push   %rbp
   0x00000000004004f9 <+1>: mov    %rsp,%rbp
   0x00000000004004fc <+4>: mov    $0x0,%eax
   0x0000000000400501 <+9>: …