小编thi*_*ser的帖子

如何使用ajax jquery上传多个图像而无需提交按钮上传？有人可以帮助我找出问题所在吗？

<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />  
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js">     </script> 

这是代码

<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />  
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js">     </script> 

如何id在提交表单后将其转换为PHP变量？我需要将总值传递给PHP变量.请帮我解决这个问题.

<div class="table-responsive">
    <table class="table table-bordered">
        <tr>        
            <th>Total Price</th>
        </tr>
        <tr>                 
            <td>
                <input class="form-control1" type='text' id='txt_totalprice' name='txt_totalprice[]'/> 
            </td>
        </tr>
    </table>     
</div>

Total: <div id="totalvalue">0</div>  

这是脚本

<script type='text/javascript'>
    $('#totalvalue').click(function() {
        $.post("package.php", { 
            id: $(this).attr('id') 
        }, function(response) {
            alert(response);
        });
    });
</script>