我使用SecKeyGeneratePair创建公钥和私钥的密钥对.

视图控制器

import UIKit
import Security

class ViewController: UIViewController {

    @IBOutlet weak var textFld: UITextField!
    @IBOutlet weak var encryptedTextFld: UITextView!
    @IBOutlet weak var decryptedTextFld: UITextView!

    var statusCode: OSStatus?
    var publicKey: SecKey?
    var privateKey: SecKey?

    override func viewDidLoad() {
        super.viewDidLoad()

        let publicKeyAttr: [NSObject: NSObject] = [kSecAttrIsPermanent:true as NSObject, kSecAttrApplicationTag:"com.xeoscript.app.RsaFromScrach.public".data(using: String.Encoding.utf8)! as NSObject]
        let privateKeyAttr: [NSObject: NSObject] = [kSecAttrIsPermanent:true as NSObject, kSecAttrApplicationTag:"com.xeoscript.app.RsaFromScrach.private".data(using: String.Encoding.utf8)! as NSObject]

        var keyPairAttr = [NSObject: NSObject]()
        keyPairAttr[kSecAttrKeyType] = kSecAttrKeyTypeRSA
        keyPairAttr[kSecAttrKeySizeInBits] = 2048 as NSObject
        keyPairAttr[kSecPublicKeyAttrs] = publicKeyAttr as …

我使用swift 3,我有一个NSTableView(3列).我填写如下数据:

 func tableView(_ tableView: NSTableView, viewFor tableColumn: NSTableColumn?, row: Int) -> NSView? {

        var cellIdentifier = String()
        var cellText = String()

            switch tableColumn {
                case tablewView.tableColumns[0]?:
                    cellText = "100"
                    cellIdentifier = "Cell1"
                break

                case tablewView.tableColumns[1]?:
                    cellText = "100"
                    cellIdentifier = "Cell2"
                break

                case tablewView.tableColumns[2]?:
                    cellText = "100"
                    cellIdentifier = "Cell3"
                break

                default: break
            }

            if let view = tableView.make(withIdentifier: cellIdentifier, owner: nil) as? NSTableCellView {
                view.textField?.stringValue = cellText
                return view
            }

        return nil
    }

现在,我想在每次选择改变时对第1列的所有值求和.我怎么能意识到这一点？

这就是我想要的

我的守则

let shadowPath = UIBezierPath(rect: shadowView.bounds).cgPath
shadowView.layer.shadowColor = UIColor.grey.cgColor
shadowView.layer.shadowOffset = CGSize(width: 0, height: 1)
shadowView.layer.shadowOpacity = 0.5
shadowView.layer.masksToBounds = false
shadowView.layer.shadowPath = shadowPath
shadowView.layer.shadowRadius = 5

我想在我的UIVIew中实现完全相同的阴影.当我使用上面的代码运行我的应用程序时,它分布在4个方面.注意:阴影在两边都很薄,在中心处是粗体.

实际上我的问题是当我点击它去了一个DetailsFragment的项目.但是当我返回到我的ItemListFragment时,项目编号会增加并且会发生重复.请帮我从中恢复..先谢谢....

ItemListFragment

public class ItemsListFragment extends Fragment {
    public static final String SINGLE_ITEMS = "single_items";
    String[] mNames;
    String[] mPrices;
    int[] mImages;
    Context mContext;
    ArrayList<Data> mArrayList = new ArrayList<Data>();


    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {

        View view = inflater.inflate(R.layout.fragment_items_list, container, false);
        RecyclerView recyclerView = (RecyclerView) view.findViewById(R.id.items_list_recycler);

        String allFields = getArguments().getString(CategoryFragment.ALL_FIELD);

        assert allFields != null;
        switch (allFields) {
            case "women_clothing":
                mNames = getResources().getStringArray(R.array.women_clothing_names);
                mPrices = getResources().getStringArray(R.array.women_clothing_prices);
                mImages = DataValues.women_clothing_images;

                break;
            case "women_shoes":
                mNames = getResources().getStringArray(R.array.women_shoes_names);
                mPrices = getResources().getStringArray(R.array.women_shoes_prices); …

我创建了一个表格视图，并且用一个手指无法单击tableViewCell，但是当我尝试用两个手指单击tableViewCell时，将发生单击事件。我不知道为什么会这样。我在tableView中创建了一个自定义单元格。

邀请函

import UIKit

class InvitePeopleVC: UIViewController, UITextFieldDelegate, UITableViewDelegate, UITableViewDataSource {

    var nameArray = ["Alwin Lazar", "Ajith Ramesh CR", "Ebrahim KK", "Vishnu Prakash"]
    var emailArray = ["alwin@xeoscript.com", "ajith@xeoscript.com", "ebrahim@xeoscript.com", "vishnu@xeoscript.com"]

    @IBOutlet weak var tableView: UITableView!
    @IBOutlet weak var doneImg: UIImageView!
    @IBOutlet weak var nameTextFld: UITextField!
    override func viewDidLoad() {
        super.viewDidLoad()
        delegates()
        uiModifications()
        gestureRecognizers()
    }

    func delegates() {
        tableView.dataSource = self
        tableView.delegate = self
        nameTextFld.delegate = self
    }

    func uiModifications() {
        nameTextFld.attributedPlaceholder = NSAttributedString(string: "Name or email address", attributes: [NSForegroundColorAttributeName: UIColor.white]) …

我在地图上有一个标记。滚动地图时，标记也会移动。我可以找到标记坐标，但如何使用该坐标查找位置信息？

当前位置的地点信息

func locate() {
        placesClient.currentPlace(callback: { (placeLikelihoodList, error) -> Void in
            if let error = error {
                print("Pick Place error: \(error.localizedDescription)")
                return
            }
            
            let placeInfo = getCurrentPlaceInformation()
            self.placeNameLbl.text = placeInfo.name
            self.placeAddressLbl.text = placeInfo.address
            
            if let placeLikelihoodList = placeLikelihoodList {
                let place = placeLikelihoodList.likelihoods.first?.place
                if let place = place {
                    print("LOG: place name : \(place.name), place Address : \(place.formattedAddress)")
                    
                    PLACE_NAME = place.name
                    PLACE_ADDRESS = place.formattedAddress ?? ""
                    
                    let placeInfo = getCurrentPlaceInformation()
                    self.placeNameLbl.text = placeInfo.name
                    self.placeAddressLbl.text = placeInfo.address
                }
            }
        }) …