小编S. *_*zor的帖子

以下代码在gcc中向我发出警告,我违反了严格的别名规则:

struct Base {
  int field = 2;
};

template <typename T>
struct Specialization: public Base {
  void method() {
      Specialization copy;
      field = copy.field;
  }
};

int main() {
    Specialization<int> s;
    s.method();
}

警告:解除引用类型惩罚指针将>破坏严格别名规则[-Wstrict-aliasing] field = copy.field;

当我删除模板时,似乎编译得很好.

struct Base {
  int field = 2;
};

struct Specialization: public Base {
  void method() {
      Specialization copy;
      field = copy.field;
  }
};

int main(){
    Specialization s;
    s.method();
}

我真的打破严格的别名规则还是GCC产生假阳性？

我-Wstrict-aliasing=3 -O3在GCC8上使用