小编arc*_*1ve的帖子

我有以下PHP代码段:

function getFacilities($testName, $dbAdapter) {
  $sql1 = "SELECT * FROM facilities_db WHERE facility_name = '$testName'";
  $result1 = $dbAdapter->query($sql1);

  $facility_details = array();
  while ($row = mysqli_fetch_assoc($result1))
  {
    $facility_details[] = $row;
  }
  return $facility_details;
}

$testName = "Abraham Moss Leisure";
$facility_data = getFacilities($testName, $mysqli);

$ testName的值是任意的,仅用于测试目的.这是其中一个答案的函数,但我在初始定义中的唯一区别是没有将$ dbAdapter作为参数.