小编pat*_*jay的帖子

当表单提交时，如果验证触发 true 比它在 form.submit() 上的显示错误；

 submitHandler: function(form) {
                    debug: true,
                    success1.show();
                    error1.hide();
                    form.submit();
                }

form html like this 
     <form method="post" id="clientordeR_create12" onsubmit="enableItemtax();"
                              action="<?php echo base_url('Clientorder/save'); ?>">

 all input eliments here

     <input type="submit" name="submit" class="btn green"
                                                   value="Save &amp; Print" formtarget="_blank" id="spSlip"/>
    </form>