小编vir*_*966的帖子

Quickblox:无法通过FCM获取推送通知获得错误401

我想在FCM的应用程序中实现推送通知.该应用程序成功获得FCM推送,但当我想从Quickblox管理pannel发送,然后给我错误像

error_description":"无法发送通知20860148,收到错误401(未经授权,请检查您的应用程序auth_key.)

这是log.json文件: -

{"notification":{"registration_ids":["dA_lOjHQU2M:APA91bHB0zGuoalZoxtdcstBQ0dL0pPJA5HyUaoPVibD2iqnrUA51NLqrrmY5zrTZV7OaP55nUEber9NLkPs_ENkVtHLvbEAcHTrgh8wl_YoNhRsUNdyeIWt0mPDKk0tCDyLssXRuFu8"],"delay_while_idle":false,"data":{"message":"hii tesas","collapse_key":"event12616627"},"priority":"high","time_to_live":86400},"
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日志 ":[{" device_token ":NULL," created_at ":" 2016-12-14T09:56:50Z " "delivered_at":NULL, "failed_at": "2016-12-14T09:56:51Z"," error_code":401,"error_description":"无法发送通知20860148,收到错误401(未经授权,请检查您的应用程序auth_key.)"}]}

android http-status-code-401 google-cloud-messaging quickblox firebase-cloud-messaging

3
推荐指数
1
解决办法
836
查看次数

AWS AppSync Error - AWSMobileClientStore.get(String) on null object reference

APPSYNC_ERROR: Attempt to invoke virtual method
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java.util.Map com.amazonaws.mobile.client.AWSMobileClientStore.get(java.lang.String[]) on a null object reference

I am trying to inserting data in AWS table, But i got this error. Can you help me to resolve this issue?

AWSAppSyncClient client = AWSAppSyncClient.builder()
                .context(context)
                .region(AppHelper.cognitoRegion)
                .serverUrl(AppHelper.SERVER_URL)
                .cognitoUserPoolsAuthProvider(new CognitoUserPoolsAuthProvider() {
                    @Override
                    public String getLatestAuthToken() {
                        try {
                            return AWSMobileClient.getInstance().getTokens().getIdToken().getTokenString();
                        } catch (Exception e){
                            Log.e("APPSYNC_ERROR", e.getLocalizedMessage());
                            return e.getLocalizedMessage();
                        }
                    }
                }).persistentMutationsCallback(new PersistentMutationsCallback() {
                @Override
                public void onResponse(PersistentMutationsResponse response) {
                    Log.d("NOTERROR", response.getMutationClassName());
                }

                @Override
                public void onFailure(PersistentMutationsError …
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android amazon-web-services aws-sdk aws-appsync appsync-apollo-client

1
推荐指数
1
解决办法
1193
查看次数

0
推荐指数
1
解决办法
4790
查看次数