我试图IntStream从一个n维int数组中获得一个.有一个很好的API方法吗?我知道两个流的连接方法.
我写了一个hello world程序来看看curses库是如何工作的.
这是我的计划:
/Users/snihalani/dev/daas at 10:10AM
? cat main.c
#include <stdio.h>
#include <stdlib.h>
#include <curses.h>
int main(void)
{
int returnValue = 0;
while(1)
{
printf("I got %d\n", getch());
}
return 0;
}
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我跑了 gcc main.c
我有
/Users/snihalani/dev/daas at 10:14AM
? gcc main.c
Undefined symbols for architecture x86_64:
"_stdscr", referenced from:
_main in ccEvUdhx.o
"_wgetch", referenced from:
_main in ccEvUdhx.o
ld: symbol(s) not found for architecture x86_64
collect2: ld returned 1 exit status
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我不知道出了什么问题.有人可以帮忙吗?
我正在尝试创建在我的类的构造函数中声明的静态映射.该地图将在一种方法中初始化并填充数据,并在另一种方法中免费使用.这是正确的方法吗?
using namespace std;
#include <map>
struct a {
string b;
string c;
}
class aClass:public myClass
{
public:
aClass();
virtual ~aClass();
private:
map<string, a> myMap;
void method(int a);
void amethod(int b);
}
void aClass::method(int a)
{
myMap = new map<string, a>;
// Addition of elements;
}
void aClass::amethod(int b)
{
// retrival of elements
myMap.clear();
delete myMap;
}
Run Code Online (Sandbox Code Playgroud) 我看到以下代码,想知道编码器的意图。它是自动装箱的相关性能吗?
map.put("doesntMatter", Boolean.TRUE);
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他本可以这样做:
map.put("doesntMatter", true);
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做第一个有什么好处吗?
bool hasId(string id, vector<User>& map)
{
User ans = *(find_if(map.begin(), map.end(), [&](User d)
{ return (id==(d).uid());}));
return ans.uid() == id;
}
Run Code Online (Sandbox Code Playgroud) void MazeSolver::solveMaze()
{
stack<Cell> myStack;
Cell current = myVector.getAt(0, 0);
myStack.push_back(current);
int x, y;
while (myStack.size() != 0)
{
current = myStack.pop_back();
x = current.x_coord;
y = current.y_coord;
}
}
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我收到以下编译时错误:
/Users/snihalani/dev/c++rec/c++hw at 7:11PM
? main.cpp: In member function 'void hw1::MazeSolver::solveMaze()':
main.cpp:55:17: error: 'class std::stack<hw1::Cell>' has no member named 'push_back'
main.cpp:59:31: error: 'class std::stack<hw1::Cell>' has no member named 'pop_back'
[1] + 18262 exit 1 g+ --std=c++11 main.cpp
在此先感谢您的帮助.
c++ ×3
java ×3
autoboxing ×1
compilation ×1
curses ×1
debugging ×1
deprecated ×1
java-8 ×1
java-stream ×1
map ×1
stl ×1