小编dot*_*cks的帖子

我正在研究一个PHP类方法,用PDO将表单值插入到mysql数据库中.这个想法概述如下,但我无法弄清楚如何传递方法的第四个参数.有人可以解释如何做到这一点？

谢谢!

<?php
class Contact {
   private $DbHost = DB_HOST;
   private $DbName = DB_NAME;
   private $DbUser = DB_USER;
   private $DbPass = DB_PASS;

   public function MySqlDbInsert($DbTableName, $DbColNames, $DbValues, $DbBindParams){
    try{
        $dbh = new PDO("mysql:host=$this->DbHost;dbname=$this->DbName",$this->DbUser,$this->DbPass, array(PDO::ATTR_PERSISTENT => true));
        $dbh->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
        $dbh->exec("SET CHARACTER SET utf8");

        $sth = $dbh->prepare("INSERT INTO $DbTableName($DbColNames) VALUES ($DbValues)");
        // i know this is all wrong ----------------
        foreach($DbBindParams as $paramValue){
            $sth->bindParam($paramValue);
        }
        // ----------------------------------------
        $sth->execute();
    }
    catch(PDOException $e){
        $this->ResponseMessage(true, 'Database access FAILED!');
    }
}

$object = new Contact(); …