我有以下df:
+---+----+-----+
|sno|dept|color|
+---+----+-----+
| 1| fn| red|
| 2| fn| blue|
| 3| fn|green|
+---+----+-----+
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如果任何颜色列值是red,那么我应该更新颜色列的所有值red,如下所示:
+---+----+-----+
|sno|dept|color|
+---+----+-----+
| 1| fn| red|
| 2| fn| red|
| 3| fn| red|
+---+----+-----+
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我无法理解.请帮忙; 我试过以下代码:
val gp=jdbcDF.filter($"dept".contains("fn"))
//.withColumn("newone",when($"dept"==="fn","RED").otherwise("NULL"))
gp.show()
gp.map(
row=>{
val row1=row.getAs[String](1)
var row2=row.getAs[String](2)
val make=if(row1 =="fn") row2="red"
Row(row(0),row(1),make)
}
).collect().foreach(println)
Run Code Online (Sandbox Code Playgroud) 我有超过30个字符串的列表。如何将列表转换为数据框。我试过的
例如
Val list=List("a","b","v","b").toDS().toDF()
Output :
+-------+
| value|
+-------+
|a |
|b |
|v |
|b |
+-------+
Expected Output is
+---+---+---+---+
| _1| _2| _3| _4|
+---+---+---+---+
| a| b| v| a|
+---+---+---+---+
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任何对此的帮助。