小编sat*_*ish的帖子

如何在tomcat服务器上部署spring boot Web应用程序

我已经创建了spring boot web应用程序,但我无法在tomcat上部署spring boot web应用程序WAR文件,我可以将其作为java应用程序运行.如何在tomcat上将spring boot应用程序作为Web服务运行.我正在使用以下代码.如果可以在tomcat上运行,请在不使用web.xml和使用web.xml的情况下帮助我使用注释.

@SpringBootApplication
public class Application extends SpringBootServletInitializer {

    protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
       return application.sources(Application.class);
    }

    public static void main(String[] args) throws Exception {
       SpringApplication.run(Application.class, args);
    }

}
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以下代码为休息控制器

@RestController
public class HelloWorld{

   @RequestMapping(value = "/hello", method = RequestMethod.GET)
   public ResponseEntity<String> get() {
       return new ResponseEntity<String>("Hello World", HttpStatus.OK);
   }
}
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我正在使用Pom.xml

<groupId>org.springframework</groupId>
<artifactId>web-service</artifactId>
<version>0.1.0</version>

<parent>
    <groupId>org.springframework.boot</groupId>
    <artifactId>spring-boot-starter-parent</artifactId>
    <version>1.3.0.RELEASE</version>
</parent>

<dependencies>
    <dependency>
        <groupId>org.springframework.boot</groupId>
        <artifactId>spring-boot-starter-web</artifactId>
    </dependency>
    <dependency>
            <groupId>org.springframework.boot</groupId>
            <artifactId>spring-boot-starter-tomcat</artifactId>
        </dependency>

        <dependency>
        <groupId>org.springframework</groupId>
        <artifactId>spring-beans</artifactId>
    </dependency>
        <dependency>
        <groupId>org.springframework</groupId>
        <artifactId>spring-webmvc</artifactId> …
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java spring tomcat spring-mvc maven

25
推荐指数
3
解决办法
7万
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Apache Spark 将多行连接成单行列表

我需要从源表创建一个表(hive 表/spark 数据框),该表将多行用户的数据存储到单行列表中。

User table:
Schema:  userid: string | transactiondate:string | charges: string |events:array<struct<name:string,value:string>> 
----|------------|-------| ---------------------------------------
123 | 2017-09-01 | 20.00 | [{"name":"chargeperiod","value":"this"}]
123 | 2017-09-01 | 30.00 | [{"name":"chargeperiod","value":"last"}]
123 | 2017-09-01 | 20.00 | [{"name":"chargeperiod","value":"recent"}]
123 | 2017-09-01 | 30.00 | [{"name":"chargeperiod","value":"0"}]
456 | 2017-09-01 | 20.00 | [{"name":"chargeperiod","value":"this"}]
456 | 2017-09-01 | 30.00 | [{"name":"chargeperiod","value":"last"}]
456 | 2017-09-01 | 20.00 | [{"name":"chargeperiod","value":"recent"}]
456 | 2017-09-01 | 30.00 | [{"name":"chargeperiod","value":"0"}]
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输出表应该是

userid:String | concatenatedlist :List[Row]
-------|-----------------
123    | …
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hive scala apache-spark apache-spark-sql

1
推荐指数
1
解决办法
9613
查看次数