小编ama*_*emi的帖子

我遇到以下错误来自" http://static.example.com "的字体已被阻止通过跨源资源共享策略加载:请求中没有"Access-Control-Allow-Origin"标头资源.因此,不允许来源" http://www.example.com "访问.

我在下面的.htaccess文件中使用以下COR设置

<IfModule mod_expires.c>
  ExpiresActive on
  ExpiresDefault "access plus 1 month"
  ExpiresByType text/cache-manifest "access plus 0 seconds"

  ........

  <IfModule mod_headers.c>
     Header append Cache-Control "public"
     <FilesMatch "\.(ttf|otf|eot|woff|svg)$">
       SetEnvIf Origin "^http://(.*)?example.com$" origin_is=$0
       Header set Access-Control-Allow-Origin %{origin_is}e env=origin_is
     </FilesMatch>
     <FilesMatch "\.(js|css|xml|gz)$">
       Header append Vary: Accept-Encoding
     </FilesMatch>
  </IfModule>
</IfModule>

我需要帮助

我需要帮助完整安装PHP7(ZTS)+ Pthreads.我尝试了以下安装,但无法使其正常工作.

sudo -i

apt-get update

apt-get install -y git bison autoconf build-essential pkg-config gitcore libltdl-dev libbz2-dev libxml2-dev libxslt1-dev libssl-dev libicu-dev libpspell-dev libenchant-dev libmcrypt-dev libpng-dev libjpeg8-dev libfreetype6-dev libmysqlclient-dev libreadline-dev libcurl4-openssl-dev

mkdir /etc/php7

mkdir /etc/php7/cli

cd /usr/local/src

git clone https://github.com/php/php-src.git --depth=1

cd php-src/ext

git clone https://github.com/krakjoe/pthreads -b master pthreads

cd ..

./buildconf --force

php_configure_args="--prefix=/etc/php7 --with-config-file-path=/etc/php7/cli --with-config-file-scan-dir=/etc/php7/cli/conf.d --with-bz2 --with-zlib --enable-zip --with-mcrypt --with-openssl --with-curl --enable-ftp --with-mysqli --enable-sockets --enable-pcntl --with-pspell --with-enchant --with-gettext --with-gd --enable-exif --with-jpeg-dir --with-png-dir --with-freetype-dir --with-xsl --enable-bcmath --enable-mbstring --enable-calendar --enable-sysvmsg --enable-sysvsem --enable-sysvshm …

我希望能够使用指针运算符对动态生成的值进行对象引用

//Jobs

class Jobs 
{
    private $orderid;
    private $quantity;
    private $contactno;
    private $contactname;
}

因此我将创建对象键

$keys = array(
    'orderid',
    'quantity',
    'contactno',
    'contactname'
);

然后做

$size = 4;
$i = 0;

//object instantiation

$jobObject = new Jobs();

$row = array('894949','45','08097577580','Emi');

for($i=0;$i<$size;$i++){

    //This is my challenge

    $jobObject->$keys[$i] = $row[$i];
}

我非常确定应该有一种方法来获取 $keys[$i] 的值，该值可以由“$jobObject->”引用来进行对象属性初始化。

我尝试用大括号将 $keys[$i] 括起来

$jobObject->{$keys[$i]} = $row[$i];

但它会抛出错误。请我需要帮助以了解如何使其正常工作或出路。