小编Chr*_*ris的帖子

如何在不增加内存的情况下连接大型列表？

请考虑以下代码段:

 Console.WriteLine($"Initial memory size: {Process.GetCurrentProcess().WorkingSet64 /1024 /1024} MB");
 int[] a = Enumerable.Range(0, 1000 * 1024 * 1024 / 4).ToArray();
 int[] b = Enumerable.Range(0, 1000 * 1024 * 1024 / 4).ToArray();
 Console.WriteLine($"Memory size after lists initialization: {Process.GetCurrentProcess().WorkingSet64 / 1024 / 1024} MB");
 List<int> concat = new List<int>();
 concat.AddRange(a.Skip(500 * 1024 * 1024 / 4));
 concat.AddRange(b.Skip(500 * 1024 * 1024 / 4));
 Console.WriteLine($"Memory size after lists concatenation: {Process.GetCurrentProcess().WorkingSet64 / 1024 / 1024} MB");

输出是:

Initial memory size: 12 MB
Memory size …

有没有办法对任何随机函数实现这一点？

class Class:
    def function(self):
        pass

import inspect
print(inspect.getlineno(Class.function))

这只是给出：

File "C:\Users\user\AppData\Local\Programs\Python\Python37-32\lib\inspect.py", line 1479, in getlineno
    return frame.f_lineno
AttributeError: 'function' object has no attribute 'f_lineno'