我在尝试编译 Vue2 项目时遇到这个问题
Syntax Error: Error: PostCSS received undefined instead of CSS string
@ ./src/assets/sass/main.scss 4:14-233 14:3-18:5 15:22-241
@ ./src/main.js
@ multi (webpack)-dev-server/client?http://192.168.1.202:8080&sockPath=/sockjs-node (webpack)/hot/dev-server.js ./src/main.js
我尝试重建 sass-loader 但没有成功。
我的节点版本是 v16.6.1 我的 NPM 版本是 7.21.0
Webpack 是 5.1.2，sass-loader 版本是 10.2.0
这是一个 VUE2 项目，当我开始一个新的 Vue3 项目时，一切都开始了，我必须升级 vue/cli 但我不明白如何返回本地（如果这是问题）
您好,我是一个使用Spring安全保护的Web应用程序,带有登录页面.这是我的安全配置
@Configuration
@ComponentScan("it.besmart")
@EnableWebSecurity
public class SecurityConfiguration extends WebSecurityConfigurerAdapter{
@Autowired
@Qualifier("customUserDetailsService")
UserDetailsService userDetailsService;
@Autowired
CustomSuccessHandler customSuccessHandler;
@Autowired
CustomAuthenticationFailureHandler customAuthenticationFailureHandler;
@Autowired
DataSource dataSource;
@Autowired
private ConnectionFactoryLocator connectionFactoryLocator;
@Autowired
private UsersConnectionRepository usersConnectionRepository;
@Autowired
private FacebookConnectionSignup facebookConnectionSignup;
private final static Logger logger = LoggerFactory.getLogger(SecurityConfiguration.class);
@Autowired
public void configureGlobalService(AuthenticationManagerBuilder auth) throws Exception {
auth.userDetailsService(userDetailsService).passwordEncoder(passwordEncoder());
}
@Bean
public PasswordEncoder passwordEncoder() {
return new BCryptPasswordEncoder();
}
protected void configure(HttpSecurity http) throws Exception {
logger.debug("Webapp security configured");
http.
authorizeRequests()
.antMatchers("/", "/register", "/registrationConfirm", "/resendRegistrationToken", "/park/**")
.permitAll()
.antMatchers("/edit/**", "/payment/**", …我正在解决这个问题...我有一个带有 S2S 通信的 Spring Boot 应用程序。我有一个@RestController应该接受 POST 请求的方法。
这是控制器
@RestController
public class PaymentRestController {
@PostMapping("/util/paymentResponse")
public void savePaymentResponse(@RequestParam boolean transaction_status, @RequestParam String usedToken,
@RequestParam String transaction_message, @RequestParam String authCode,
@RequestParam String transactionCode, @RequestParam String orderId, HttpServletRequest request) {
//business logic
}
}
如果我点击此链接，我会收到 405 错误，方法不允许
第一次我发现请求被 Web 应用程序上启用的 CSFR 过滤器阻止，所以我以这种方式配置了我的安全性
@Configuration
@ComponentScan("it.besmart")
@EnableWebSecurity
public class SecurityConfiguration extends WebSecurityConfigurerAdapter{
@Autowired
@Qualifier("customUserDetailsService")
UserDetailsService userDetailsService;
@Autowired
CustomSuccessHandler customSuccessHandler;
@Autowired
CustomAuthenticationFailureHandler customAuthenticationFailureHandler;
@Autowired
DataSource dataSource;
private final static Logger logger = LoggerFactory.getLogger(SecurityConfiguration.class); …我有一个Spring Boot应用程序.它在2台服务器上运行.服务器具有相同的配置.其中一个是有效的...另一方面,我在启动时遇到此异常
2016-04-26 08:24:17.633 ERROR [localhost-startStop-1]: Error starting Tomcat context: org.springframework.beans.factory.BeanCreationException
2016-04-26 08:24:17.903 ERROR [main]: Application startup failed
org.springframework.context.ApplicationContextException: Unable to start embedded container; nested exception is org.springframework.boot.context.embedded.EmbeddedServletContainerException: Unable to start embedded Tomcat
at org.springframework.boot.context.embedded.EmbeddedWebApplicationContext.onRefresh(EmbeddedWebApplicationContext.java:133)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:532)
at org.springframework.boot.context.embedded.EmbeddedWebApplicationContext.refresh(EmbeddedWebApplicationContext.java:118)
at org.springframework.boot.SpringApplication.refresh(SpringApplication.java:766)
at org.springframework.boot.SpringApplication.createAndRefreshContext(SpringApplication.java:361)
at org.springframework.boot.SpringApplication.run(SpringApplication.java:307)
at org.springframework.boot.SpringApplication.run(SpringApplication.java:1191)
at org.springframework.boot.SpringApplication.run(SpringApplication.java:1180)
at it.besmart.parkserver.StartServer.main(StartServer.java:13)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:497)
at org.springframework.boot.loader.MainMethodRunner.run(MainMethodRunner.java:54)
at java.lang.Thread.run(Thread.java:745)
Caused by: org.springframework.boot.context.embedded.EmbeddedServletContainerException: Unable to start embedded Tomcat
at org.springframework.boot.context.embedded.tomcat.TomcatEmbeddedServletContainer.initialize(TomcatEmbeddedServletContainer.java:99)
at org.springframework.boot.context.embedded.tomcat.TomcatEmbeddedServletContainer.<init>(TomcatEmbeddedServletContainer.java:76)
at org.springframework.boot.context.embedded.tomcat.TomcatEmbeddedServletContainerFactory.getTomcatEmbeddedServletContainer(TomcatEmbeddedServletContainerFactory.java:457)
at org.springframework.boot.context.embedded.tomcat.TomcatEmbeddedServletContainerFactory.getEmbeddedServletContainer(TomcatEmbeddedServletContainerFactory.java:168) …大家早上好,我正在处理一个不能解码的模糊映射...我正在使用Spring mvc 4.0.6和hibernate 4.3.6我在tomcat中启动战争时遇到此错误:
ERROR [localhost-startStop-2]: Context initialization failed
org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'requestMappingHandlerMapping' defined in class org.springframework.web.servlet.config.annotation.DelegatingWebMvcConfiguration: Invocation of init method failed; nested exception is java.lang.IllegalStateException: Ambiguous mapping found. Cannot map 'appController' bean method
public java.lang.String it.besmart.controller.AppController.newClient(org.springframework.ui.ModelMap)
to {[//new],methods=[POST],params=[],headers=[],consumes=[],produces=[],custom=[]}: There is already 'appController' bean method
public java.lang.String it.besmart.controller.AppController.saveClient(it.besmart.models.Client,org.springframework.validation.BindingResult,org.springframework.ui.ModelMap) mapped.
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1553)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:539)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:475)
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:302)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:228)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:298)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:193)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:703)
at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:760)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:482)
at org.springframework.web.context.ContextLoader.configureAndRefreshWebApplicationContext(ContextLoader.java:403)
at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:306)
at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:106)
at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:4727) …我试图在 bootstrap-vue 表中创建一个插槽，以使用自定义组件呈现任何布尔值。
所以我有一个简单的表
<b-table :items="items" :fields="columns" >
</b-table>
现在，如果我想以特定方式呈现单个列，我必须使用插槽
<template v-slot:cell(active)="data" >
<my-component :item="data.item" />
</template>
它有效，因为我知道这active是一个布尔值。
我想概括这种行为，但我不能v-for在模板中使用，v-slot:cell(active)如果不在模板上也不能使用......这个想法是创建一个包含我所有布尔字段的数组并对其进行迭代......但它不起作用......
像这样的东西
<template v-slot:cell(b)="data" v-for="b in booleanFields">
<my-component :item="data.item[b]" />
</template>
我正在使用 Spring security 并使用编码器对密码进行编码。
因此，在我的 Spring Security Config 中，我已自动连接
PasswordEncoder passwordEncoder()并将其添加到 中DaoAuthenticationProvider，这是我的 Spring Security 配置
package it.besmart.easyparking.config;
import javax.sql.DataSource;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.beans.factory.annotation.Qualifier;
import org.springframework.context.annotation.Bean;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.authentication.dao.DaoAuthenticationProvider;
import org.springframework.security.config.annotation.authentication.builders.AuthenticationManagerBuilder;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.configuration.EnableWebSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
import org.springframework.security.core.userdetails.UserDetailsService;
import org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder;
import org.springframework.security.crypto.password.PasswordEncoder;
import org.springframework.security.web.authentication.rememberme.JdbcTokenRepositoryImpl;
import org.springframework.security.web.authentication.rememberme.PersistentTokenRepository;
import org.springframework.security.web.servlet.support.csrf.CsrfRequestDataValueProcessor;
import org.springframework.web.servlet.support.RequestDataValueProcessor;
@Configuration
@EnableWebSecurity
public class SecurityConfiguration extends WebSecurityConfigurerAdapter {
@Autowired
@Qualifier("customUserDetailsService")
UserDetailsService userDetailsService;
@Autowired
CustomSuccessHandler customSuccessHandler;
@Autowired
CustomAuthenticationFailureHandler customAuthenticationFailureHandler;
@Autowired
DataSource dataSource;
@Autowired
public void configureGlobalSecurity(AuthenticationManagerBuilder auth) …我已经为此奋斗了好几天，在这里我已经阅读了所有讨论，但是没有解决方案...
我有一个自定义约束。
独特的.java
@Target({FIELD, METHOD})
@Retention(RUNTIME)
@Constraint(validatedBy = UniqueConstraintValidator.class)
public @interface Unique {
String message() default "{src.main.resources}";
Class<?>[] groups() default {};
Class<? extends Payload>[] payload() default {};
String property() default "id";
Class<?> entity();
}
这由UniqueConstraintValidator.java使用
@Transactional
public class UniqueConstraintValidator implements ConstraintValidator<Unique, Serializable> {
private static final Logger logger = Logger.getLogger(UniqueConstraintValidator.class);
Session session;
@Autowired
private SessionFactory sessionFactory;
protected Session getSession(){
return sessionFactory.getCurrentSession();
}
private Class<?> entityClass;
private String uniqueField;
public void initialize(Unique unique) {
entityClass = unique.entity();
uniqueField = unique.property(); …我正在尝试使用 spring 的授权授予流程来保护我的 REST Api。
我可以（使用 Postman）获取访问令牌，我将授权放入带有 Bearer 的标头中，但是我无法访问资源，因为 Spring Security 告诉我：
2017-04-06 17:36:33 [http-nio-8080-exec-9] DEBUG o.s.s.w.c.HttpSessionSecurityContextRepository[186] - HttpSession returned null object for SPRING_SECURITY_CONTEXT
2017-04-06 17:36:33 [http-nio-8080-exec-9] DEBUG o.s.s.w.c.HttpSessionSecurityContextRepository[116] - No SecurityContext was available from the HttpSession: org.apache.catalina.session.StandardSessionFacade@6e24700e. A new one will be created.
2017-04-06 17:36:33 [http-nio-8080-exec-9] DEBUG o.s.s.w.h.writers.HstsHeaderWriter[130] - Not injecting HSTS header since it did not match the requestMatcher org.springframework.security.web.header.writers.HstsHeaderWriter$SecureRequestMatcher@3e385c64
2017-04-06 17:36:33 [http-nio-8080-exec-9] DEBUG o.s.security.web.FilterChainProxy[325] - /api/user at position 11 of 14 in additional filter chain; firing Filter: …我正在尝试实现一个自定义 HttpStatus 代码系统来提供有关我的 REST 服务的错误信息。
为此，我实现了一个新的枚举 CustomHttpStatus
public enum CustomHttpStatus {
ERROR1(42, "Error 1"),
ERROR2(43, "Error 2"),
ERROR3(44, "Error 3"),
ERROR4(45, "Error 4"),
ERROR5(46, "Error5");
private CustomHttpStatus(int value, String reason) {
this.value = value;
this.reason = reason;
}
private final int value;
private final String reason;
public int getValue() {
return value;
}
public String getReason() {
return reason;
}
}
然后，我有一个类，它携带有关错误的信息并管理标准 HTTPStatus 和我的 CustomHttpStatus
public class ApiError {
private HttpStatus status;
private CustomHttpStatus customStatus;
private String message;
private List<String> …