我正在尝试实现一个自定义 HttpStatus 代码系统来提供有关我的 REST 服务的错误信息。
为此，我实现了一个新的枚举 CustomHttpStatus
public enum CustomHttpStatus {
ERROR1(42, "Error 1"),
ERROR2(43, "Error 2"),
ERROR3(44, "Error 3"),
ERROR4(45, "Error 4"),
ERROR5(46, "Error5");
private CustomHttpStatus(int value, String reason) {
this.value = value;
this.reason = reason;
}
private final int value;
private final String reason;
public int getValue() {
return value;
}
public String getReason() {
return reason;
}
}
然后，我有一个类，它携带有关错误的信息并管理标准 HTTPStatus 和我的 CustomHttpStatus
public class ApiError {
private HttpStatus status;
private CustomHttpStatus customStatus;
private String message;
private List<String> …我在使用 Spring JPA 并尝试检索对象列表时遇到了这个问题。
这是我试图检索的课程
@Entity
@Table(name="OBJECTSTERMIC")
public class TermicObject {
@Id
@Column(name="TERMICID")
private long termicId;
@MapsId
@OneToOne(fetch = FetchType.LAZY)
@JoinColumn(name="OBJECTID",columnDefinition="INTEGER")
private Object object;
@Column(name="CONTECA_RIF")
private int contecaRif;
@Column(name="CONTECA_VAL")
private int contecaVal;
@Column(name="TYPE")
private String type;
//getters and setters
该Object班有存储为整数MySQL的主键，这的确是Object
@Entity
public class Object {
@Column(name="OBJECTID")
@Id
@JsonProperty("OBJECTID")
private int objectId;
....
所以，无处设置长...
现在，我只是调用一个服务类
@Override
public List<TermicObject> findAll() {
return repository.findAll();
}
并得到了这个例外
org.springframework.dao.InvalidDataAccessApiUsageException: org.hibernate.TypeMismatchException: Provided id of the wrong type for class it.besmart.db_eipo.persistence.model.Object. Expected: class java.lang.Integer, got …我正在使用 Spring Security 来管理我的 Web 应用程序中的身份验证。使用它，我可以根据用户名管理对某些对象的访问。
因此，在我的 DAO 级别中，我有这个方法，它为我提供了用户的 Park 对象列表
public List<Park> findParkByUser(int offset) {
Authentication auth = SecurityContextHolder.getContext().getAuthentication();
List<Park> parks = new ArrayList<Park>();
try {
if(auth != null){
String name = auth.getName();
User user = userService.findBySso(name);
int userId = user.getId();
Criteria criteria = createEntityCriteria();
criteria.createAlias("users", "u");
if(offset >= 0){
criteria.add(Restrictions.eq("u.id", userId)).setFirstResult(offset).setMaxResults(elementsPerPage);
}
criteria.setResultTransformer(Criteria.DISTINCT_ROOT_ENTITY);
parks = (List<Park>) criteria.list();
} else {
logger.debug("Auth error");
}
} catch (NullPointerException e) {
logger.error("Auth error",e);
}
return parks;
}
现在的问题是，当会话超时或cookie过期时，我会得到一个nullauth。我想将用户重定向到登录页面，但我处于 DAO …
我有一个TiimerTask，应该基于Timer.schedule运行。问题是，它仅在应用程序启动时运行一次...也许这有待解决，但我不明白是什么...
这是我的类，它扩展了TimerTask
public class ClientScheduler extends TimerTask {
public String serverUrl = Start.getHost();
public String append = "/client/checkVersion";
public String numeroClient = null;
public String actualVersion = null;
public String filePrefix = "eparkclient-";
public String fileSuffix = "-jar-with-dependencies.jar";
private final Logger logger = Logger.getLogger(ClientScheduler.class);
public ClientScheduler() {
}
@Override
public void run() {
logger.debug("Scheduler starts");
String finalUrl = null;
try {
numeroClient = PropertyConfig.getClientId();
actualVersion = PropertyConfig.getFirmwareVersion();
finalUrl = serverUrl + append + "?numeroClient=" + numeroClient;
HttpConnection http = new …我想将带有JQuery的POST请求发送到Spring Controller，但我不断从jquery收到此错误
Could not read document: Unrecognized token 'contactForm': was expecting ('true', 'false' or 'null')
at [Source: java.io.PushbackInputStream@38220bcd; line: 1, column: 13]; nested exception is com.fasterxml.jackson.core.JsonParseException: Unrecognized token 'contactForm': was expecting ('true', 'false' or 'null')
at [Source: java.io.PushbackInputStream@38220bcd; line: 1, column: 13]
这是POST请求
$('#contactForm').on('submit', function(e){
e.preventDefault();
var contactForm = new Object;
var firstName = $('#firstName').val();
var lastName = $('#lastName').val();
var email = $('#email').val();
var message = $('#message').val();
contactForm.firstName = firstName;
contactForm.lastName = lastName;
contactForm.email = email;
contactForm.message = message;
contactForm.accepted …我们有一个Spring Boot应用程序,它链接到该领域的各种客户端.该应用程序具有一个控制器,该控制器从客户端调用并与DB和物理开关交互,以关闭或打开灯.
当两个或多个客户端访问服务器上的API时会出现问题,因为该方法会检查指示灯是打开还是关闭(在数据库上)以更改其状态.如果指示灯熄灭,并且2个客户端同时调用该服务,则第一个打开指示灯并更改数据库上的状态,但第二个访问指示灯也是如此,数据库上的状态为OFF但是第一个客户端已经调整了灯光,所以秒钟最终将其关闭以为打开它...也许我的解释有点不清楚,问题是:我可以告诉spring当时访问控制器一个请求吗？
感谢下面的答案,我们对切换开关的方法引入了悲观锁定,但我们继续从客户那里得到200状态......
我们正在使用spring boot + hibernate
现在控制器有悲观锁定的例外
try {
String pinName = interruttore.getPinName();
// logger.debug("Sono nel nuovo ciclo di
// gestione interruttore");
if (!interruttore.isStato()) { // solo se
// l'interruttore
// è
// spento
GpioPinDigitalOutput relePin = interruttore.getGpio()
.provisionDigitalOutputPin(RaspiPin.getPinByName(pinName));
interruttoreService.toggleSwitchNew(relePin, interruttore, lit); // accendo
interruttore.getGpio().unprovisionPin(relePin);
}
} catch (GpioPinExistsException ge) {
logger.error("Gpio già esistente");
} catch (PessimisticLockingFailureException pe){
logger.error("Pessimistic Lock conflict", pe);
return new ResponseEntity<Sensoristica>(sensoristica, HttpStatus.CONFLICT);
}
toggleSwitchNew 如下
@Override
@Transactional(isolation=Isolation.REPEATABLE_READ)
public void toggleSwitchNew(GpioPinDigitalOutput relePin, Interruttore interruttore, boolean …我有一个以这种方式制作的路由器视图对象
export default new Router({
linkExactActiveClass: 'active', // active class for *exact* links.
mode: 'history',
routes: [
{
path: '/admin',
name: 'dashboard',
component: Dashboard
},
{
path: '/company',
name: 'company',
component: ObjectList,
props: {
url: '/web/company',
idColumn: 'companyId'
}
}
]
})
当我点击 /company 链接时，路由器正确地将我发送到ObjectList组件
在这个页面中，我有一个以这种方式制作的简单分页组件
<template>
<div class="overflow-auto">
<b-pagination-nav
align="center"
:link-gen="linkGen"
:number-of-pages="totalPages"
use-router
></b-pagination-nav>
</div>
</template>
<script>
export default {
data() {
return {
};
},
name: "pagination",
props: {
current: Number,
url: String,
totalPages: Number
}, …我阅读了有关我的问题的所有问题，但都没有成功...我正在将与Maven的战争分配给我，我希望它可以在另一个IP上的tomcat服务器上使用。
我遵循了所有设置...
我的插件的POM
<plugin>
<groupId>org.apache.tomcat.maven</groupId>
<artifactId>tomcat7-maven-plugin</artifactId>
<version>2.2</version>
<configuration>
<url>http://192.168.3.67:8080/manager/text</url>
<server>TomcatServer</server>
<path>webapp</path>
</configuration>
</plugin>
我的/conf/settings.xml for tomcat有
<server>
<id>TomcatServer</id>
<username>maven</username>
<password>maven</password>
</server>
并且tomcat-user.xml如下
<role rolename="manager-gui"/>
<role rolename="manager-script"/>
<user username="system" password="raspberry" roles="manager-gui"/>
<user username="maven" password="maven" roles="manager-script"/>
当我尝试部署应用程序时，我得到了
[INFO] Deploying war to http://192.168.3.67:8080/manager/webapp
Uploading: http://192.168.3.67:8080/manager/text/deploy?path=webapp
2472/14845 KB
[INFO] I/O exception (java.net.SocketException) caught when processing request: Broken pipe
[INFO] Retrying request
Uploading: http://192.168.3.67:8080/manager/text/deploy?path=webapp
2384/14845 KB
[INFO] I/O exception (java.net.SocketException) caught when processing request: Broken pipe
[INFO] Retrying request
Uploading: http://192.168.3.67:8080/manager/text/deploy?path=webapp
2398/14845 KB
[INFO] I/O …我有一个运行Mysql和Hibernate的Spring Boot应用程序。
启动它时，出现此错误
Unsuccessful: alter table SMARTPARK.illuminazione add constraint FK_4kmtr3q9e2hnaoutsxgahhm63 foreign key (id_interruttore) references SMARTPARK.interruttori (id_interruttore)
2016-05-05 08:46:35 ERROR SchemaUpdate:262 - Cannot add foreign key constraint
我有两个表/实体
Illuminazione.java是（只是有趣的部分...）
@Entity
@Table(name = "illuminazione", catalog = "SMARTPARK")
public class Illuminazione {
private int idilluminazione;
private Interruttore interruttore;
private Date dateTime;
private Date lastDateTime;
private boolean isLit;
@ManyToOne
@JoinColumn(name = "id_interruttore")
public Interruttore getInterruttore() {
return this.interruttore;
}
public void setInterruttore(Interruttore interruttore) {
this.interruttore = interruttore;
}
在Interruttore.java中，我@OneToMany与Illuminazione 有关系
@Entity
@Table(name …我正在使用带引导程序的 datetimepicker。
一切顺利，然后我尝试使用 2 个日期时间选择器来选择一个日期间隔，但是当我尝试选择一个日期时，我进入了控制台
TypeError: $('#datetimepicker2').data("DateTimePicker").maxDate is not a function. (In '$('#datetimepicker2').data("DateTimePicker").maxDate(e.date)', '$('#datetimepicker2').data("DateTimePicker").maxDate' is undefined)
我正在使用来自https://eonasdan.github.io/bootstrap-datetimepicker/ 的bootstrap-datetimepicker
（maxDate 也会出现一些错误）
这是我正在调用的脚本
$(function() {
$('#datetimepicker2').datetimepicker({
locale : 'it',
format : 'DD/MM/YYYY HH:mm'
});
$('#datetimepicker3').datetimepicker({
locale : 'it',
format : 'DD/MM/YYYY HH:mm',
useCurrent: false //Important! See issue #1075
});
$("#datetimepicker2").on("dp.change", function (e) {
$('#datetimepicker3').data("DateTimePicker").minDate(e.date);
});
$("#datetimepicker3").on("dp.change", function (e) {
$('#datetimepicker2').data("DateTimePicker").maxDate(e.date);
});
});
我错过了什么吗？
我刚开始休眠,我正试图解决一些我无法理解的问题......
例如,我有这个查询
Query query = session.createQuery("from Client where clientId = "+clientId+")");
List result = query.list();
我的Client.hbm.xml是
<class name="it.besmart.models.Client" table="client" catalog="SMARTPARK">
<id name="idClient" type="int">
<column name="id_client" />
<generator class="identity" />
</id>
<property name="nomeClient" type="string">
<column name="nome_client" length="65535" not-null="true" />
</property>
<property name="numPosti" type="int">
<column name="num_posti" not-null="true" />
</property>
<property name="numLuci" type="int">
<column name="num_luci" not-null="true" />
</property>
<property name="inizioPosti" type="int">
<column name="inizio_posti" not-null="true" />
</property>
<property name="inizioLuci" type="int">
<column name="inizio_luci" not-null="true" />
</property>
</class>
</hibernate-mapping>
DB上的表称为客户端,列为client_id
hibernate.cfg.xml中的映射是
<hibernate-configuration>
<session-factory name="parkserver">
<property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property> …我正在尝试用授权代码流保护我的休息api,但我不明白为什么我收到消息:
User must be authenticated with Spring Security before authorization can be completed.
我有一个具有User和Admin访问权限的应用程序的Web部分,以及带有2个不同授权的REST api部分,/ api/**授权代码和带有client_credentials的/ oauth2/**.
client_credential流程工作,但授权代码nope ...
所以,这是我的授权服务器配置
@Configuration
@EnableAuthorizationServer
public class AuthorizationServerConfig extends AuthorizationServerConfigurerAdapter {
@Autowired
DataSource dataSource;
@Autowired
@Qualifier("authenticationManagerBean")
private AuthenticationManager authManager;
@Override
public void configure(AuthorizationServerSecurityConfigurer oauthServer) throws Exception {
oauthServer.tokenKeyAccess("permitAll()").checkTokenAccess("isAuthenticated()");
}
@Override
public void configure(ClientDetailsServiceConfigurer clients) throws Exception {
clients.jdbc(dataSource);
}
@Override
public void configure(AuthorizationServerEndpointsConfigurer endpoints) throws Exception {
endpoints.tokenStore(tokenStore()).authenticationManager(authManager);
}
@Bean
public TokenStore tokenStore() {
return new JdbcTokenStore(dataSource);
}
}
这是我的资源服务器配置
@Configuration
@EnableResourceServer
@EnableGlobalMethodSecurity(prePostEnabled=true) …