我在提交表单后尝试将新行数据推送到表中.但是,调用的表UrlListCtrl与表单不同,即UrlFormCtrl.
function UrlFormCtrl($scope, $timeout, UrlService) {
$scope.message = '';
var token = '';
$scope.submitUrl = function(formUrls) {
console.log('Submitting url', formUrls);
if (formUrls !== undefined) {
UrlService.addUrl(formUrls).then(function(response){
$scope.message = 'Created!';
// I need to update the view from here
});
} else {
$scope.message = 'The fields were empty!';
}
}
在UrlFormCtrl,我发送一个数组到数据库进行存储,之后我想更新视图,在哪里UrlListCtrl处理它.
function UrlListCtrl($scope, $timeout, UrlService){
UrlService.getUrls().then(function(response){
$scope.urls = response.data;
});
}
我正在尝试将新数据推送到$scope.url.这是服务:
function UrlService($http) {
return {
addUrl: addUrl,
getUrls: getUrls …我一直在尝试开发一个Minecraft服务器插件,其中玩家输入带有一些数据的命令,数据被发送到数据库,或者从数据库请求一些数据的命令.
它正在工作,直到用户开始使用它多次.我收到了泄漏检测错误:
[HikariPool-2 housekeeper] WARN com.zaxxer.hikari.pool.ProxyLeakTask - Connection leak detection triggered for com.mysql.jdbc.JDBC4Connection@abc6eb, stack trace follows
[23:36:11 WARN]: java.lang.Exception: Apparent connection leak detected
或者我得到一个错误,告诉我有太多的连接.(对不起,我此刻没有这个错误)
这是我的代码的要点.我做错了什么？
public class MochaModel {
private Latte instance = Latte.getInstance();
private Connection connection;
public MochaModel() {
}
public void createTable() {
BukkitRunnable r = new BukkitRunnable() {
@Override
public void run() {
try {
connection = Database.getConnection();
if (connection != null) {
String sql = "CREATE TABLE IF NOT EXISTS `mocha` ( " +
" `id` …我需要创建Woocommerce如何处理订单,以便我可以创建订单Site A并将订单发送到Site B.
因此,当客户将项添加到他们的购物车,然后单击结账时,它都创造了秩序Site A和Site B,但是,它也重定向到用户Site B处理付款.
到目前为止,我只能更改结帐按钮:
add_filter( 'woocommerce_get_checkout_url', 'my_change_checkout_url', 30 );
function my_change_checkout_url( $url ) {
$url = "your checkout url ";
return $url;
}
并创建订单.
if (isset($_POST['isOrder']) && $_POST['isOrder'] == 1) {
$address = array(
'first_name' => $_POST['notes']['domain'],
'last_name' => '',
'company' => $_POST['customer']['company'],
'email' => $_POST['customer']['email'],
'phone' => $_POST['customer']['phone'],
'address_1' => $_POST['customer']['address'],
'address_2' => '',
'city' => $_POST['customer']['city'],
'state' => '',
'postcode' => $_POST['customer']['postalcode'],
'country' => …我试图直接将通过 KonvasJS 动态添加到画布的图像居中。
这是小提琴：
http://jsfiddle.net/71Lw0bk8/7/
我已经弄清楚了代码，但它没有使用 Konva，而是尝试在没有库的情况下执行此操作，并且效果完美。
function addImage(imgUrl) {
const img = new Image();
img.onload = function () {
var padding = 20;
while (img.width + padding > canvas.width || img.height + padding > canvas.height) {
if (img.width + padding > canvas.width) {
let newWidth = canvas.width - (padding * 2);
img.height = Math.round((img.height / img.width) * newWidth);
img.width = newWidth;
}
else if (img.height + padding > canvas.height) {
let newHeight = canvas.height - (padding * 2);
img.width …