小编Jaw*_*Mmm的帖子

如果我声明并使用这样的指针:

int counter;
char *pCow = "pCow goes MOO";

for(counter = 0; counter < 14; counter++)
    printf("%c", pCow[counter]);

它显示整个字符串并且工作,是的,并且有很多欢乐.

但是,如果我使用这样的初始化器:

int counter;
char *pCow = {'p','C','o','w',' ','g','o','e','s',' ','M','O','O','\0'};

for(counter = 0; counter < 14; counter++)
    printf("%c", pCow[counter]);

程序崩溃了,pCow拒绝为我的享乐主义乐趣而呻吟!

3 Warnings. 0 Errors
line 11 (near initialization for 'pCow') [enabled by default]   C/C++ Problem
line 11 excess elements in scalar initializer [enabled by default]  C/C++ Problem
line 11 initialization makes pointer from integer without a cast [enabled by default]   C/C++ Problem …

刚开始使用K&R并点击:

#include <stdio.h>
/* copy input to output; 1st version */
main()
{
    int c;
    c = getchar();
    while (c != EOF) {
        putchar(c);
        c = getchar();
    }
}

它只显示我输入的内容,即使它是一串文本.

cacti
cacti
stop repeating what i'm saying
stop repeating what i'm saying

就像那样.

我没有得到的是为什么我不能用一串文本实例化变量c并以相同的方式打印它.(为了示例而忽略while循环)与:

main()
{
    int c;

    c = "cacti";
    putchar(c);
}

其中输出显然只是'd'