小编Rya*_*_DS的帖子

我有一个简单的猜数游戏.它具有询问您是否需要提示的功能.它将响应保存在boolean调用中tips,如图所示.

while (run) {
    while (tinvalidrun){
        System.out.println("Do you want any tips? y or n?");
        input=in.next();
        switch(input){
        case "y":
            System.out.println("Ok, we will tell you how close you are!");
            tinvalidrun=false;
            tips=true;
            break;
        case "n":
            System.out.println("Wanna go hard eh? Well, go along!");
            tinvalidrun=false;
            break;
        default:
            System.out.println("You pressed the wrong key!\nDo you have butter fingers?");
        }
    }

然后我有一些代码可以生成更多变量并生成一个随机数.最后我得到猜测的用户输入并测试它:

do {
    System.out.println("Enter a number: ");
    guess = in.nextByte();
    times++;
    if (guess == gval) {
        break;
    } else {
        System.out.println("No luck! Try …

假设我有一个列表,

Arrays.asList("A","B","C","D");

Java中是否有一种便捷方法允许我检查此列表以查看元素C和D是否按此顺序列在此列表中？

有点像:

Collections.containsOrderedElements(list,"C","D");
Collections.containsOrderedElements(list,"A","B","C");

上述方法将返回true但是

Collections.containsOrderedElements(list,"A","C");

将不会？

感谢您的时间.