小编Har*_*hil的帖子

在我的项目中,我使用TimePicker对话框允许用户选择时间.但我不希望他们选择分钟.所以,我想要的是禁用(或隐藏)分钟选择.那么,怎么做？

我需要帮助来完成以下脚本：

import socket
import struct
import sys
import time

NTP_SERVER = '0.uk.pool.ntp.org'
TIME1970 = 2208988800L

def sntp_client():
    client = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    data = str.encode('\xlb' + 47 * '\0')
    client.sendto(data, (NTP_SERVER, 123))
    data, addr = client.recvfrom(1024)
    if data:
        print('Response received from:', addr)
    t = struct.unpack('!12I', data)[10]
    t -= TIME1970
    print('\tTime: %s' % time.ctime(t))

if __name__ == '__main__':
    sntp_client()

预期输出：

Response received from: ('80.82.244.120', 123)
      Time: Tue Sep 13 14:49:38 2016

问题是程序没有给出任何输出。看起来它卡在：

data, addr = client.recvfrom(1024)

我希望有人能帮我解决这个问题。

实际上我正在构建一个需要用户位置的应用程序.但是我收到了SERVICE_VERSION_UPDATE_REQUIRED错误.以下是我的MainActivity.java和AndroidManifest.xml文件:

MainActivity.java

TextView lat, lon;
private static final String TAG = MainActivity.class.getSimpleName();

private FusedLocationProviderApi locationProvider = LocationServices.FusedLocationApi;
private GoogleApiClient googleApiClient;
private LocationRequest locationRequest;
private double latitude, longitude;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    lat = (TextView) findViewById(R.id.lat);
    lon = (TextView) findViewById(R.id.lon);

    if (googleApiClient == null) {
        googleApiClient = new GoogleApiClient.Builder(this)
                .addApi(LocationServices.API)
                .addConnectionCallbacks(this)
                .addOnConnectionFailedListener(this)
                .build();
    }

    locationRequest = new LocationRequest();
    locationRequest.setInterval(10000);
    locationRequest.setFastestInterval(1000);
    locationRequest.setPriority(LocationRequest.PRIORITY_HIGH_ACCURACY);
}

@Override
public void onConnected(@Nullable Bundle bundle) {
    requestLocationUpdates();
} …