小编Wiz*_*zix的帖子

我正在尝试将数据从csv文件转换为热图.目前,我的热图如下所示:

但它错过了一个传奇!这是我的代码:

import matplotlib.pyplot as plt
import numpy as np

column_labels = list(range(0,24))
row_labels = ["Lundi",
              "Mardi",
              "Mercredi",
              "Jeudi",
              "Vendredi",
              "Samedi",
              "Dimanche"]
data = np.array([
                [0,0,0,0,0,0,0,0,0,0,434,560,650,340,980,880,434,434,0,0,0,0,0,0],
                [0,0,0,0,0,0,0,434,560,0,650,0,0,0,0,340,980,0,0,0,880,0,434,343],
                [0,0,0,0,0,0,0,0,0,0,434,560,650,340,980,880,434,434,0,0,0,0,0,0],
                [0,0,0,0,0,0,0,434,560,0,650,0,0,0,0,340,980,0,0,0,880,0,434,343],
                [0,0,0,0,0,0,0,0,0,0,434,560,650,340,980,880,434,434,0,0,0,0,0,0],
                [0,0,0,0,0,0,0,434,560,0,650,0,0,0,0,340,980,0,0,0,880,0,434,343],
                [0,0,0,0,0,0,0,0,0,0,434,560,650,340,980,880,434,434,0,0,0,0,0,0]
                ])
fig, axis = plt.subplots() # il me semble que c'est une bonne habitude de faire supbplots
heatmap = axis.pcolor(data, cmap=plt.cm.Blues) # heatmap contient les valeurs

axis.set_yticks(np.arange(data.shape[0])+0.5, minor=False)
axis.set_xticks(np.arange(data.shape[1])+0.5, minor=False)

axis.invert_yaxis()

axis.set_yticklabels(row_labels, minor=False)
axis.set_xticklabels(column_labels, minor=False)

fig.set_size_inches(11.03, 3.5)

plt.savefig('test.png', dpi=100)

我怎么能有这个情节的传奇？就像在这一个:

非常感谢你的帮助 !

我正在学习 Sequelize，我发现有些东西很奇怪，所以我认为我做错了什么。

这是我对一个简单Posts表的迁移：

'use strict';
module.exports = {
    up: (queryInterface, Sequelize) => {
        return queryInterface.createTable('Posts', {
            id: {
                allowNull: false,
                autoIncrement: true,
                primaryKey: true,
                type: Sequelize.INTEGER
            },
            title: {
                type: Sequelize.STRING,
                allowNull: false,
            },
            content: {
                type: Sequelize.TEXT,
                allowNull: false,
            },
            authorId: {
                type: Sequelize.INTEGER,
                onDelete: 'CASCADE',
                allowNull: false,
                references: {model: 'Users', key: 'id'}
            },
            publishedAt: {
                type: Sequelize.DATE,
                allowNull: true
            },
            createdAt: {
                allowNull: false,
                type: Sequelize.DATE
            },
            updatedAt: {
                allowNull: false,
                type: Sequelize.DATE
            }
        });
    }, …

我有两个模型,用户和事件.我invitations用一个status列在User和Event之间创建了一个数据透视表.在我的事件模型定义中,我写了这样的:

public function invited()
{
    return $this->belongsToMany(User::class, 'invitations', 'event_id', 'user_id')
        ->withTimestamps()
        ->withPivot('status')
        ->orderByDesc('invitations.updated_at');
}

public function participants()
{
    $event = $this->with([
        'invited' => function ($query) {
            $query->where('invitations.status', InvitationStatus::ACCEPTED)->get();
        }
    ])->first();

    return $event->invited;
}

但是当我在我的控制器中时:

$event = Event::where('id', $id)->with(['owner', 'participants'])->first();

我有以下错误:

(1/1) BadMethodCallException
Method addEagerConstraints does not exist.

有人知道为什么吗？

我被困在这个我认为很简单的问题上。我有一个结构定义和一个采用该结构实例的函数。如何在 Ada 中调用此函数？这是一个示例代码：

定义.h：

typedef struct cartesian_t
{
    float x;
    float y;
    float z;
} cartesian_t;

void debug_cartesian(struct cartesian_t t);

定义.c

void debug_cartesian(struct cartesian_t t)
{
    printf("%f, %f, %f\n", t.x, t.y, t.z);
}

主文件

with Interfaces.C; use Interfaces.C;
with Ada.Text_IO;

procedure Main is
    type Cartesian_Record_Type is record
        X : C_Float;
        Y : C_Float;
        Z : C_Float;
    end record
    with
        Convention => C;
        
    procedure Debug_Cartesian(Cart : in Cartesian_Record_Type)
    with
        Import => True,
        Convention => C,
        External_Name => "debug_cartesian";


    T : Cartesian_Record_Type …

目前正在学习 Ada 并真正享受它，有一个问题困扰着我：什么是tagged类型？根据 John Barnes 的 Programming in Ada 2012，它表示实例化的对象在运行时带有标签。

我在 C++ 或 CI 中从未听说过这样的事情，所以我有点迷茫。它是什么？我什么时候需要它（显然是为了拥有方法和继承？）？

我正在尝试使用Tweepy的用户的最后一条推文.这是我的代码:

class Bot:
    def __init__(self, keys):
        self._consumer_key = keys[0]
        self._consumer_secret = keys[1]
        self._access_token = keys[2]
        self._access_secret = keys[3]

        try:
            auth = tweepy.OAuthHandler(self._consumer_key,
                                       self._consumer_secret)
            auth.set_access_token(self._access_token, self._access_secret)

            self.client = tweepy.API(auth)
            if not self.client.verify_credentials():
                raise tweepy.TweepError
        except tweepy.TweepError as e:
            print('ERROR : connection failed. Check your OAuth keys.')
        else:
            print('Connected as @{}, you can start to tweet !'.format(self.client.me().screen_name))
            self.client_id = self.client.me().id


    def get_last_tweet(self):
        tweet = self.client.user_timeline(id = self.client_id, count = 1)
        print(tweet.text)
        # AttributeError: 'ResultSet' object has no attribute 'text'

我理解错误,但如何从状态中获取文本？Tweepy的文档很糟糕且不完整......

非常感谢您的帮助,
祝您度过愉快的一天!:)

我在rand项目中添加了依赖项：

[dependencies]
rand = "0.5"

在我的中main.rs，我具有以下内容：

extern crate rand;

pub mod foo;
use foo::Foo;

fn main() {
    println!("{:#?}", Foo::new());
}

并在文件中foo.rs：

use rand::Rng;

#[derive(Debug)]
pub struct Foo { bar: bool }

impl Foo {
    pub fn new() -> Foo {
        Foo { bar: rand::thread_rng().gen_bool(0.5) }
    }
}

当我尝试编译它时，出现以下错误：

error[E0658]: access to extern crates through prelude is experimental (see issue #44660)
  --> src\foo.rs:11:18
   |
11 |             bar: rand::thread_rng().gen_bool(0.5)
   |                  ^^^^

如何使用模块中的外部包装箱？

我正在努力做到这一点

local ball = {
        width = 20,
        height = 20,

        position = {
            x = (game.width / 2) - (width / 2), -- Place the ball at the center of the screen
            y = (game.height / 2) - (height / 2)
        },

        velocity = 200,
        color = { 255, 255, 255 }
    }

但Love2D说我attempt to perform arithmetic on global 'width' (a nil value).我该如何解决？
我已经尝试过替换width / 2,ball.width / 2但我得到了attempt to index global 'ball' …

我正在尝试为程序生成随机字符串ID(该ID必须在程序执行期间才是唯一的).我首先在Python中做到没有任何问题:

class RandomIdGenerator:
    _base_62_chars = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"

    @classmethod
    def get_base_62(cls, length):
        return "".join([random.choice(RandomIdGenerator._base_62_chars) for _ in range(length)])

但是因为我需要我的程序使用C++,所以我试图用它生成相同的字符串.这就是我现在所做的:

void Node::setId()
{
    QString allow_symbols("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789");
    qsrand(QTime::currentTime().msec());

    for (int i = 0; i < ID_LENGTH; ++i) {
        id_.append(allow_symbols.at(qrand() % (allow_symbols.length())));
    }
}

我有两个主要问题.首先它不使用C++ 11(我不知道Qt是如何工作的,但我不认为它是C++ 11)并且生成的ID都是相同的.如果我生成其中四个我得到:

"R4NDM1xM"
"R4NDM1xM"
"R4NDM1xM"
"R4NDM1xM"

我尝试使用C++ 11方法但是我得到了相同的结果,更糟糕的是,在每次执行时,我得到了完全相同的结果:

void Node::setId()
{
    id_ = "";

    const std::string str = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";

    std::random_device rd;
    std::mt19937 generator(rd());
    std::uniform_int_distribution<int> dist(0, str.size() - 1);

    for (int i = 0; i < Node::ID_LENGTH; ++i)
        id_ += str[dist(generator)];
} …

当我不想在 Rust 匹配结构中做任何事情时，我可以执行以下两种方法之一：

match some_number {
    1 => println!("One"),
    2 => (), // unit value
    _ => {}  // ?
}

有什么区别吗？{}不是单位值，那么它有什么作用呢？