我有叫3个表tbl_monday,tbl_tuesday并tbl_wednesday认为由数据如下:
tbl_monday
id empid Plan
---------------------
1 6 Mon_27
2 6 Mon_27
3 6 Mon_27
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tbl_tuesday
id empid Plan
--------------------
1 6 Tue_28
2 6 Tue_28
3 6 Tue_28
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tbl_wenesday
id empid Plan
------------------
1 6 Wed_29
2 6 Wed_29
3 6 Wed_29
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有没有简单的方法来获得这样的结果?
empid Plan
----------------------
6 Mon_27
6 Tue_28
6 Wed_29
Run Code Online (Sandbox Code Playgroud) 这是我创建的异步函数,这里在将这个函数强加到按钮上时出现错误.
public async Task<bool> Login(string UserName, string Password)
{
try
{
ParseUser User = await ParseUser.LogInAsync(UserName, Password);
System.Windows.Forms.MessageBox.Show(User.ObjectId);
var currentUser = ParseUser.CurrentUser;
return true;
}
catch (Exception ex)
{
System.Windows.Forms.MessageBox.Show(ex.Message);
return false;
}
}
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调用时收到错误.
private void btnLogin_Click(object sender, EventArgs e)
{
if (Login(txtUserName.Text,txtPassword.Text))
{
MessageBox.Show("Login Success");
}
}
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