小编Its*_*nas的帖子

当我尝试编译我的C++项目时,我收到错误消息调用隐式删除的'std :: array'的默认构造函数.

头文件cubic_patch.hpp

#include <array>
class Point3D{
public:
    Point3D(float, float, float);
private:
    float x,y,z;
};

class CubicPatch{
public:
    CubicPatch(std::array<Point3D, 16>);
    std::array<CubicPatch*, 2> LeftRightSplit(float, float);
    std::array<Point3D, 16> cp;
    CubicPatch *up, *right, *down, *left;
};

源文件cubic_patch.cpp

#include "cubic_patch.hpp"
Point3D::Point3D(float x, float y, float z){
    x = x;
    y = y;
    z = z;
}

CubicPatch::CubicPatch(std::array<Point3D, 16> CP){// **Call to implicitly-deleted default constructor of 'std::arraw<Point3D, 16>'**
    cp = CP;
}

std::array<CubicPatch*, 2> CubicPatch::LeftRightSplit(float tLeft, float tRight){
    std::array<CubicPatch*, 2> newpatch;
    /* …

我正在学习 C++11 中的条件变量，并根据示例代码编写了这个程序。

目标是将生产者生成并由消费者推入向量的前十个自然整数累积在向量中。然而它不起作用，因为例如在某些运行中，向量仅包含 1、7 和 10。

#include <mutex>
#include <condition_variable>
#include<vector>
#include <iostream>
#include <cstdio>

std::mutex mut;
#define MAX     10
int counter;
bool isIncremented = false;
std::vector<int> vec;
std::condition_variable condvar;

void producer() {
    while (counter < MAX) {
        std::lock_guard<std::mutex> lg(mut);
        ++counter;
        isIncremented = true;
        condvar.notify_one();
    }
}

void consumer() {
    while (true) {
        std::unique_lock<std::mutex> ul(mut);
        condvar.wait(ul, [] { return isIncremented; });
        vec.push_back(counter);
        isIncremented = false;
        if (counter >= MAX) {
            break;
        }
    }
}

int main(int argc, char *argv[]) …