小编Son*_*man的帖子

我只想在 WPF 页面之间切换，但出现上述错误：页面只能将 Window 或 Frame 作为父级。这是我的代码

Imports System.Windows.Forms

公开课第1页

Private Sub btn1_Click(sender As Object, e As RoutedEventArgs) Handles btn1.Click
    Try

        Dim dd As New Page2


        Me.Content = dd
        Me.txt1.Text = (dd.txt10.Text)
    Catch ex As Exception

        txt1.Text = ex.Message
    End Try

xaml 文件代码

<Page x:Class="Page2"
  xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
  xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
  xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" 
  xmlns:d="http://schemas.microsoft.com/expression/blend/2008" 
  mc:Ignorable="d" 
  d:DesignHeight="300" d:DesignWidth="300"
  Title="Page2">
<Grid>

    <Button x:Name="button1" Content="Button" HorizontalAlignment="Left" Margin="163,62,0,0" VerticalAlignment="Top" Width="101" Height="55"/>
    <TextBox x:Name="txt10" HorizontalAlignment="Left" Height="23" Margin="38,81,0,0" TextWrapping="Wrap" Text="TextBox" VerticalAlignment="Top" Width="120"/>

</Grid>

请指导我我做错了什么？

我是java的新手,我只是尝试从Deployment Descriptor文件(web.xml)中读取初始化参数,但是出现了上述错误？

我web.xml和java文件编码编码附加快照.

我的直接结构是

c:\....tomcat\webapps\dd\web-inf\classes

java类文件中没有错误.

成功编译的Java文件代码

import java.io.*; 
import java.net.*; 
import javax.servlet.*;
import javax.servlet.http.*;

public class MyServlet2 extends HttpServlet { 

    String fileName; 
    public void init(ServletConfig config) throws ServletException {
        super.init(config); 
        fileName = config.getInitParameter("logfilename"); 
    } 

    protected void doGet(HttpServletRequest request,HttpServletResponse response)throws ServletException, IOException { 
         processRequest(request, response); 
    } 

    protected void doPost(HttpServletRequest request,HttpServletResponse response)throws ServletException, IOException { 
         processRequest(request, response); 
    } 

    protected void processRequest(HttpServletRequest request,HttpServletResponse 
response)throws ServletException, IOException { 
          PrintWriter out = response.getWriter(); 
          out.println(fileName); 
          out.close(); 
    } 
}

web.xml中

<?xml version="1.0" encoding="ISO-8859-1"?> 
<web-app> …