Python的Decorator函数有这个简单的模板
@A
@B
def C():
它将C函数修改为C = A(B(C));
让我们举一个更具体的例子
@request("POST", "%(channel)d/sequence/%(args)s")
@response("%d")
def outputSequence(self, channel, args):
self.checkDigitalChannelExported(channel)
self.checkPostingValueAllowed()
self.checkDigitalChannel(channel)
(period, sequence) = args.split(",")
period = int(period)
GPIO.outputSequence(channel, period, sequence)
return int(sequence[-1])
所以从上面来看,转换后的函数是否可以
喜欢请求(响应(outSequence(self,channel,args))？
在UIViewController中,tempview2根本没有出现.只有tempview出现了.
-(id) init:(NSData*) imageData
{
if ((self = [super init])) {
tempimage= [[[UIImage alloc] initWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"pic1" ofType:@"png"]] autorelease];
tempview=[[[UIImageView alloc] initWithFrame:CGRectMake(0, 0, 320, 480)] autorelease];
[tempview setImage:tempimage];
[self.view addsubview tempview];
}
return self;
}
-(void) viewdidload{
tempimage2= [[[UIImage alloc] initWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"pic2" ofType:@"png"]] autorelease];
tempview2=[[[UIImageView alloc] initWithFrame:CGRectMake(0, 0, 320, 480)] autorelease];
[tempview2 setImage:tempimage2];
[self.view addsubview tempview2];
}
如果我这样做,那么一切都很好,
-(id) init:(NSData*) imageData
{
if ((self = [super init])) {
tempimage= [[[UIImage alloc] initWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"pic1" ofType:@"png"]] autorelease];
tempview=[[[UIImageView alloc] initWithFrame:CGRectMake(0, … someClass myobject=new someClass("test");
List <someClass> mylist;
mylist.add(myobject);
好吧,我得到的第一个错误是mylist被初始化,所以我做了List myList = NULL; 然后它有一个警告说在mylist.add(myobject)访问NULL指针.变量mylist此时只能是NUll.
List <someClass> mylist=NULL;
所以,当我运行程序时,系统崩溃了.但是如果不设置为NULL,编译器也会有一个错误,说它没有初始化.
我可以做一个./adb install -r myapp.apk
成功
然后我马上做一个./db unistall myapp.apk
然后它列出了失败.没有其他消息
我在php server.php中有一个套接字服务器
$master = WebSocket("localhost",800);
$sockets = array($master);
$users = array();
$debug = false;
function WebSocket($address,$port)
{
$master=socket_create(AF_INET, SOCK_STREAM, SOL_TCP) or die("socket_create() failed");
socket_set_option($master, SOL_SOCKET, SO_REUSEADDR, 1) or die("socket_option() failed");
socket_bind($master, $address, $port) or die("socket_bind() failed");
socket_listen($master,20) or die("socket_listen() failed");
echo "Server Started : ".date('Y-m-d H:i:s')."\n";
echo "Master socket : ".$master."\n";
echo "Listening on : ".$address." port ".$port."\n\n";
return $master;
}
在我的命令行上,我做到了
sudo chmod 777 /socket/websocket/server.php
然后
php -q /socket/server.php trying to bring it up.
然后有一个错误,
警告:socket_bind():无法绑定地址[13]:第60行/socket/websocket/server.php中的权限被拒绝
第60行是
socket_bind($master, $address, …class Foo
{
public:
// single parameter constructor, can be used as an implicit conversion
Foo (int foo) : m_foo (foo)
{
}
int GetFoo () { return m_foo; }
private:
int m_foo;
};
m_foo是私有部分中定义的整数,但是m_foo(foo)是什么？看起来像一个功能.
m_foo既是整数又是函数？这是如何运作的？
而Foo(int foo)构造函数正在扩展m_foo函数.
/**
* ring_buffer_set - update the ring buffer with the given value
* @lq_recv: pointer to the ring buffer
* @lq_index: index to store the value at
* @value: value to store in the ring buffer
*/
static void ring_buffer_set(uint8_t lq_recv[], uint8_t *lq_index,
uint8_t value)
{
lq_recv[*lq_index] = value;
*lq_index = (*lq_index + 1) % 64;
}
/**
* ring_buffer_set - compute the average of all non-zero values stored
* in the given ring buffer
* @lq_recv: pointer to the …$result = mysql_query($query);
$leaderboard = array();
while($row = mysql_fetch_assoc($result)) {
$leaderboard[$row["username"]] = $row["score"];
}
$output = array
(
'status' => 1,
'content' =>$leaderboard
);
print_r(json_encode($output));
现在$output数组就是这样的JSON:
{"tim":"120","john":"45","larry":"56"}
但我希望将它们作为键值对,所以我想要像:
{"name":"tim","score":120","name":"john","score="45", etc.}
如果我需要这种方式,我如何修改$leaderboard数组,以便输出就是这样？
我有一个功能
char *func1(char *buffer);
这个函数有一个缓冲区.
char buffer[10]={'\0'};
buffer被传递给函数并从函数中获得结果并从函数返回.
所以,当Main函数调用func1时
char *result=func1(buffer);
所以当我打印结果时,它会给出一个有效的结果..
printf("The final result is %s", result);
但是,在这行代码之后
s = socket(AF_INET,SOCK_DGRAM,0);
我再次打印结果
printf("The final result is %s", result);
这次它给出了不同的结果.
我想知道为什么char * result改变了？
*(uint64_t*) mFrame->first
它是一个指针,结构然后解除引用？对我来说似乎有点费解.uint64_t定义在哪里？