我有这个SQL查询,当它运行到phpMyAdmin时它正常工作.
SELECT COUNT( * ) , LENGTH( Number ) AS Numbers
FROM `history_2015-07-22`
WHERE Number NOT LIKE '123%'
OR LENGTH( Number ) <50
GROUP BY Numbers
ORDER BY TIME = '2015-07-22 00:00:01' ASC
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我现在想制作一个简单的php页面,我想在浏览器上显示查询结果,但我无法弄清楚如何完全回应它.所以我做了这个:
$result = $pdo->prepare("SELECT COUNT( * ) , LENGTH( Number ) AS Numbers
FROM `history_2015-07-22`
WHERE Number NOT LIKE '123%'
OR LENGTH( Number ) <50
GROUP BY Numbers
ORDER BY TIME = '2015-07-22 00:00:01' ASC ");
$result->execute();
foreach ($result as $Numbers)
{
echo '<div class="container">
'.$Numbers['COUNT(*)'].'
'.$Numbers['LENGTH(Number)'].' …Run Code Online (Sandbox Code Playgroud) 可以<?php ?>在echo中输出输出吗?所以情况是这样的:
<?php
// some code
foreach ( $something as $row )
{
echo '<input type="hidden" id="'.$row["id"].'" value="<?php echo $cats; ?>">'
}
?>
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那么如何输出$cats值php部分?有可能吗?我需要的价值$cats不是整个部分htmlentities
编辑:
它不是重复的,它'.$cats.'可能不是我的折叠,我没有正确解释.
$cats 从ajax脚本的响应而不是从此查询得到它的值