我有这个SQL查询,当它运行到phpMyAdmin时它正常工作.
SELECT COUNT( * ) , LENGTH( Number ) AS Numbers
FROM `history_2015-07-22`
WHERE Number NOT LIKE '123%'
OR LENGTH( Number ) <50
GROUP BY Numbers
ORDER BY TIME = '2015-07-22 00:00:01' ASC
Run Code Online (Sandbox Code Playgroud)
我现在想制作一个简单的php页面,我想在浏览器上显示查询结果,但我无法弄清楚如何完全回应它.所以我做了这个:
$result = $pdo->prepare("SELECT COUNT( * ) , LENGTH( Number ) AS Numbers
FROM `history_2015-07-22`
WHERE Number NOT LIKE '123%'
OR LENGTH( Number ) <50
GROUP BY Numbers
ORDER BY TIME = '2015-07-22 00:00:01' ASC ");
$result->execute();
foreach ($result as $Numbers)
{
echo '<div class="container">
'.$Numbers['COUNT(*)'].'
'.$Numbers['LENGTH(Number)'].'
</div>';
}
Run Code Online (Sandbox Code Playgroud)
我想要回应的是Count和Length.我确信这是一件非常简单的事情,但我无法弄明白.
小智 6
首先,您能否解释一下您正在尝试使用SQL查询做什么?
根据我的理解,你可以试试这个:
$result = $pdo->prepare("SELECT COUNT( * ) AS ct_all, LENGTH( `Number` ) AS Numbers
FROM `history_2015-07-22`
WHERE `Number` NOT LIKE ('123%')
AND Numbers < 50
GROUP BY Numbers
ORDER BY `TIME` ASC");
$result->execute();
$results = $result->fetchAll();
foreach ($results as $row) {
echo '<div class="container">';
echo $row['ct_all'] . ' // ';
echo $row['Numbers'];
echo '</div>';
}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
226 次 |
| 最近记录: |