目前,它在每个国家查询,但我希望它只在新加坡查询
我发现了一个stackoverflow解决方案如何使用Google自动完成位置api ios sdk获取特定国家/地区的结果?,但无法弄清楚我把代码放在哪里.
这是代码,我使用全屏解决方案进行自动完成.
import UIKit
import GoogleMaps
class OnlyLocationViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
@IBAction func clickMe(sender: UIButton) {
let autocompletecontroller = GMSAutocompleteViewController()
autocompletecontroller.delegate = self
self.presentViewController(autocompletecontroller, animated: true, completion: nil)
}
}
extension OnlyLocationViewController: GMSAutocompleteViewControllerDelegate{
func viewController(viewController: GMSAutocompleteViewController, didAutocompleteWithPlace place: GMSPlace) {
print("Place name: ", place.name)
print("Place address: …Run Code Online (Sandbox Code Playgroud) 我正在探索不同的 websocket 库进行自学,我发现这个库真的很棒ws-node。我正在 ws-node 库中构建基本的一对一聊天
我的问题是ws 中的socket.io函数等价于什么?socket.to().emit()因为我想向特定用户发送消息。
前端 - socket.io
socket.emit("message", { message: "my name is dragon", userID: "123"});
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服务器端-socket.io
// listening on Message sent by users
socket.on("message", (data) => {
// Send to a specific user for 1 on 1 chat
socket.to(data.userID).emit(data.message);
});
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WS-- 后端
const express = require('express');
const http = require('http');
const WebSocket = require('ws');
const express = require('express');
const http = require('http');
const WebSocket = require('ws');
const app = express(); …Run Code Online (Sandbox Code Playgroud) 我在使用passport-instagram时遇到了麻烦,我正试图在我的应用程序中实施passport-instagram.每当我尝试使用instagram登录按钮登录时,我都会收到此错误:InternalOAuthError:无法获取访问令牌{无匹配代码}
这是代码
instagram.js(护照instagram配置文件)
var passport = require('passport');
var InstagramStrategy = require('passport-instagram').Strategy;
var User = require('../models/user');
var instaOpt = {
clientID: "aad229e3597643be92568acb46efb40d",
clientSecret: "5563070a33394e0fafada92a16ec2e71",
callbackURL: "http://localhost:8000/auth/instagram/callback"
};
var instagramInit = function(accessToken, refreshToken, profile, callback) {
User.findOne({ "instagram.id" : profile.id } , function(err, user) {
if (err) return callback(err);
if (user) {
return callback(null, user); // User already exist
}
var newUser = new User();
newUser.instagram.id = profile.id;
newUser.instagram.token = accessToken;
newUser.instagram.email = profile.email;
newUser.instagram.displayName = profile.displayName;
newUser.instagram.name = profile.name;
newUser.instagram.username …Run Code Online (Sandbox Code Playgroud) 我的问题是,无论如何我都需要初始化该特定变量,因为还有另一个对象依赖于此变量的值
这是代码(我将变量设置为global)
lazy var getToken = {
if let token = keychain["token"].string {
return token
}
}()
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我正在使用惰性,因为无论如何我都需要使用它来进行初始化。
当我尝试将其放在全局文件中时出现此错误错误
'lazy'可能不会在已经很懒惰的global上使用
这是取决于此令牌的对象
单例设计
class SocketIOManager: NSObject {
static let sharedInstance = SocketIOManager()
let socket: SocketIOClient!
private override init() {
super.init()
socket = SocketIOClient(socketURL: URL(string: mainURL)!, .connectParams(["token": getToken])])
}
}
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如果你看看socket =在"token",这就是我需要的令牌
所以我设法让passport-twitter与jsonwebtoken库一起工作,但为了使它正常工作,我必须使用express-session作为中间件.我不想添加会话因为我使用jsonwebtoken来返回令牌.
这是代码autheticate.js
router.get('/twitter', function(req, res, next){
passport.authenticate('twitter', {session: false}, function(err, user, info){
if(err){ return next(err); }
if(user){
var token = createToken(user);
console.log(token);
return res.json({token: token});
} else {
return res.status(401).json(info);
}
})(req, res, next);
});
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我已经添加了session:false作为参数,但是在server.js上它保持吐出错误,我需要使用快速会话.
server.js
var express = require('express');
var path = require('path');
var logger = require('morgan');
var bodyParser = require('body-parser');
var mongoose = require('mongoose');
var passport = require('passport');
var session = require('express-session');
var config = require('./config');
mongoose.connect('mongodb://localhost', function() {
console.log("Connected to the database");
})
require('./passport')(passport); …Run Code Online (Sandbox Code Playgroud) 我只是无法弄清楚为什么while循环中的这个简单逻辑不起作用.
基本上函数的作用是,它接受一个参数并检查while循环以查看它是否为"yes"或"no"然后继续循环.
void getAnswer(string answer) {
string newAnswer = "";
newAnswer = answer;
while (newAnswer != "Yes" || newAnswer != "yes" || newAnswer != "Y" || newAnswer != "y" || newAnswer != "No" || newAnswer != "no") {
cout << "Enter yes or no.." << endl;
cin >> newAnswer;
}
if (newAnswer == "Yes" || newAnswer == "yes" || newAnswer == "Y" || newAnswer == "y") {
chooseOptions();
} else {
cout << "Bye See you again " << endl; …Run Code Online (Sandbox Code Playgroud) 我已经使用node.js实现了条带结账
product.photo是https://test.s3.amazonaws.com/2213131
const session = await stripe.checkout.sessions.create({
payment_method_types: ["card"],
line_items: [{
name: product.title,
description: product.description,
images: [product.photo],
amount: product.price * 100,
currency: "usd",
quantity: 1
}],
success_url: "http://localhost:3000/success?session_id={CHECKOUT_SESSION_ID}",
cancel_url: "http://localhost:3000/cancel"
});
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由于某种原因,图片总是空的
其他数据没问题
auth0 实现的中间件示例
func EnsureValidToken(next http.Handler) http.Handler {
// EnsureValidToken is a middleware that will check the validity of our JWT.
err := godotenv.Load()
if err != nil {
log.Fatal("Error loading .env file")
}
issuerURL, err := url.Parse("https://" + os.Getenv("AUTH0_DOMAIN") + "/")
if err != nil {
log.Fatalf("Failed to parse the issuer url: %v", err)
}
provider := jwks.NewCachingProvider(issuerURL, 5*time.Minute)
jwtValidator, err := …Run Code Online (Sandbox Code Playgroud) 每次我在路由'localhost:8080 /'刷新一个html页面或登录用户我都会收到此错误:发送后无法设置标题.据我所知,这个问题是由于两次意外调用的回调而发生的.该应用程序不会崩溃或任何东西,它只是在控制台上记录相同的错误.
这是代码.
var User = require('../models/user');
var Story = require('../models/story');
var jwt = require('jsonwebtoken');
var config = require('../../config');
var superSecret = config.secret;
module.exports = function(app, express) {
// creating our first router
var apiRouter = express.Router();
// signup a user
apiRouter.post('/signup', function(req, res) {
var user = new User({
name: req.body.name,
username: req.body.username,
password: req.body.password
});
user.save(function(err) {
if(err) res.send(err);
res.json({ message: 'User has been created!' });
});
});
apiRouter.get('/users', function(req, res) {
User.find({}, function(err, users) { …Run Code Online (Sandbox Code Playgroud) 我将 twilio 用于 whatsapp API,但现在的问题是我不断收到此错误
错误:Twilio 找不到具有指定发件人地址的频道
这是代码
const express = require('express')
const accountSid = '-'
const authToken = '-'
const client = require('twilio')(accountSid, authToken)
const request = require('request')
const app = express()
app.get('/test', (req, res, next) => {
client.messages
.create({
body: 'Hello there!',
from: 'whatsapp:+14155238886',
to: 'whatsapp:+myNumber'
})
.then(message => console.log(message.sid))
.done()
res.json('Done')
})
app.listen(3030, (err) => {
if (err) {
console.log(err)
} else {
console.log('Connected to the port 3030')
}
})
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沙盒图片
我该怎么办?
node.js ×6
passport.js ×2
swift ×2
auth0 ×1
c++ ×1
express ×1
go ×1
go-fiber ×1
google-maps ×1
ios ×1
javascript ×1
mean-stack ×1
mongoose ×1
oauth ×1
session ×1
socket.io ×1
twilio ×1
websocket ×1