所以我有这三个文件

MAIN.C

#include <assert.h>
#include <string.h>
#include <sys/types.h>
#include <unistd.h>
#include <stdio.h>
#include "support.h"

int main( void ) {
    int* num1 = malloc(100);
    printf("num1: %p", &num1);
}

Support.c

#include <assert.h>
#include <string.h>
#include <sys/types.h>
#include <unistd.h>
#include "support.h"

void *malloc(size_t size) {
    struct block_meta *block;
    if (size <= 0) {
        return NULL;
    }
    if (!global_base) { // First call.
    block = request_space(NULL, size);
        if (!block) {
            return NULL;
        }
        global_base = block;
    } else {
        struct block_meta *last = global_base; …

如果我的List<String[]>每个人String[]都如下所示：{FirstName，LastName，Income，City}我将如何使用Java 8 lambda通过特定值（例如收入或名字）对列表进行排序？

这是我的main方法的代码,应该很明显我试图让迭代器按名称访问元素

#include <iostream>
#include <list>
#include "PC.h"
#include "SunServer.h"

using namespace std;

int main(){
    PC mypc1("John", "645.22.55.34", 128, "admin");
    PC mypc2("Mike", "645.22.55.34", 128, "admin");
    PC mypc3("Rick", "645.22.55.34", 128, "admin");
    PC mypc4("Bill", "645.22.55.34", 128, "admin");

    list<PC> my_group;

    my_group.push_front(mypc1);
    my_group.push_front(mypc2);
    my_group.push_front(mypc3);
    my_group.push_front(mypc4);
    list<PC>::iterator curr = my_group.begin();

    while (curr != mypc2){
        // do something
    }

}

现在很明显它不起作用,但有什么我可以做的,这相当于这个？谢谢