小编Kev*_*ate的帖子

我正在为我的WebSocket服务器开发一个Spring WebSocket Stomp Client,我收到了相互矛盾的信息.我找到了两种方法让它工作,而没有太多细节我想知道哪种方式被认为是实现客户端的"正确"方式.

有人可以帮我理解WebSocketConnectionManager的用途吗？

另外,还有一个问题,我如何保持websocket连接打开,程序运行以接受新消息,而不必编写System.in.read()行.

第一种方式:直接使用SockJsClient

URI uri = new URI("ws://localhost:8080/stomp");
StandardWebSocketClient simpleWebSocketClient = new StandardWebSocketClient();

List<Transport> transports = new ArrayList<>(1);
transports.add(new WebSocketTransport(simpleWebSocketClient));

SockJsClient sockJsClient = new SockJsClient(transports);
sockJsClient.setMessageCodec(new Jackson2SockJsMessageCodec());

StompMessageReceiver messageHandler = new StompMessageReceiver();
StompWebSocketHandler websocketHandler = new StompWebSocketHandler(messageHandler, new StringMessageConverter());

try {
    this.webSocketClient.doHandshake(websocketHandler, null, uri).get();
} catch (InterruptedException | ExecutionException e) {
    throw new IllegalStateException(e);
}

System.in.read();

第二种方式:使用WebSocketConnectionManager

StandardWebSocketClient simpleWebSocketClient = new StandardWebSocketClient();
List<Transport> transports = new ArrayList<>(1);
transports.add(new WebSocketTransport(simpleWebSocketClient));

SockJsClient sockJsClient = new SockJsClient(transports);
sockJsClient.setMessageCodec(new Jackson2SockJsMessageCodec()); …