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Symfony2验证器想要成为ValidatorInterface的实例

我想在Symfony2中创建一个表单,所以我按照本网站上的教程进行操作

namespace Project\Foo\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Project\Foo\Entity\Anfrage;
use Symfony\Component\HttpFoundation\Request;

class UploadController extends Controller
{

public function indexAction(Request $request)
{
    $anfrage = new Anfrage();
    $anfrage->setName('Güntaa');
    $anfrage->setAge(5);
    $anfrage->setEmail('foo@foo.de');

    $form = $this->createFormBuilder($anfrage)
        ->add('save', 'submit', array('label' => 'Create Task'))
        ->getForm();

    return $this->render(
        'Foo:Upload:index.html.twig',
        array(
            'title' => 'Foo',
            'form' => $form->createView(),
        ));
    }
}
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在我的模板中,我想调用此表单:

{{ form_start(form) }}
{{ form_widget(form) }}
{{ form_end(form) }}
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但是当我调用我的模板时,我收到以下错误:

Validator必须是Symfony\Component\Validator\Validator\ValidatorInterface或Symfony\Component\Validator\ValidatorInterface的实例

我不知道,如何解决这个问题.

编辑

这是Anfrage实体:

<?php   

namespace Project\MarkupConverterBundle\Entity;

class Anfrage {

    protected $name;
    protected $age;
    protected $email; …
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php forms validation symfony symfony-2.5

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forms ×1

php ×1

symfony ×1

symfony-2.5 ×1

validation ×1