错误信息:
runfile('// rschfs1x/userrs/xd73_RS/Documents/Python Scripts/test_515.py',wdir ='// rschfs1x/userrs/xd73_RS/Documents/Python Scripts')
文件"// rschfs1x/userrs/xd73_RS/Documents/Python Scripts/test_515.py",第120行
Run Code Online (Sandbox Code Playgroud)if __name__ == "__main__": ^SyntaxError:语法无效
真的不确定为什么会出现这个问题
def sendemail(alertmessage):
msg = MIMEText(alertmessage)
msg['Subject'] = 'Patent Data Error Message'
msg['From'] = "patentcornell@gmail.com"
msg['To'] = "patentcornell@gmail.com"
# Credentials (if needed)
username = 'patentcornell@gmail.com'
password = ''
# The actual mail send
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login(username,password)
server.sendmail("hello", "xd73@cornell.edu", alertmessage)
server.sendmail("hello", "jq58@cornell.edu", alertmessage)
#server.sendmail("hello", "sl2448@cornell.edu", alertmessage)
server.sendmail("hello", "patentcornell@gmail.com", alertmessage)
'''
Shanjun Li <sl2448@cornell.edu>,
Panle Barwick <pjb298@cornell.edu>,
Jing Qian <jq58@cornell.edu>
'''
server.quit()
def main(year …Run Code Online (Sandbox Code Playgroud) 我想用数字创建一个字符串。所以我将字符串数组的长度定义为 10,但是当我在控制台中启动程序时是 11 个字符。
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#define N 10
using namespace std;
int main()
{
srand(time(0));
int numArr[N];
for(int i = 0; i < N; i++)
numArr[i] = rand() % 26 + 97;
for(int i = 0; i < N; i++)
std::cout << numArr[i] << " ";
std::cout << std::endl;
char str[N] = "";
for(int i = 0; i < N; i++)
str[i] = numArr[i];
std::cout << str << endl;
std::cout << strlen(str);
return …Run Code Online (Sandbox Code Playgroud) 我正在 Visual Studio Code 中尝试 tkinter,但没有显示此代码的窗口(只是测试):
from tkinter import *
Tk()
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我是否错过了任何安装?
在运行时使用 for 循环语句初始化字符数组时,会像 printf 函数一样执行两次,同时 6 大小的字符数组只需要 3 个输入:
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main() {
int i = 0;
char name[6];
for (int i = 0; i < 5; ++i)
{
printf("Enter the character in name array");
scanf("%c", &name[i]);
}
printf("%s", name);
return 0;
}
Run Code Online (Sandbox Code Playgroud) stud_dict={'Ali':'Math 90 physics 85','taha':'Math 88 physics 70','lara':'Math 80 physics 90'}
print(stud_dict)
import pandas as pd
df=pd.DataFrame({stud_dict})
print(df)
Run Code Online (Sandbox Code Playgroud) 有没有办法生成代码(在编译时),看起来有点像:
T Func(T t){
if (sizeof(t) == 2){
return X(t);
}
else if( sizeof(t) == 4){
return Y(t);
}
}
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(其中T是int32或int16)
所以在运行时我可以打电话:
Func(_myInt)
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代码将编译为任何一个X(_myInt)或Y(_myInt).
所以我在看这段代码:
#include <stdio.h>
struct Student {
int id;
char name[32];
} s, *sp;
int main() {
printf("sizeof(structStudent) = %u\n", sizeof(structStudent));
printf("sizeof(s) = %u\n", sizeof(s));
printf("sizeof(structStudent*) = %u\n", sizeof(structStudent*));
printf("sizeof(sp) = %u\n", sizeof(sp));
return 0;
}
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输出如下:
sizeof(struct Student) = 36
sizeof(s) = 36
sizeof(struct Student*) = 4
sizeof(sp) = 4
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为什么尺寸为struct Student*4,为什么尺寸sp也是4?我的powerpoint没有详细说明这一点.我知道为什么的大小struct Student和s为36:因为32个char(对于一个字节+4字节int)= 36总.
# Python Version\n\n\xce\xbb python\nPython 3.7.0b5 (v3.7.0b5:abb8802389, May 31 2018, 01:54:01) [MSC v.1913 64 bit (AMD64)] on win32\nType "help", "copyright", "credits" or "license" for more information.\n>>>\n\n\n\n\n\xce\xbb pip3 install web.py\nCollecting web.py\n Using cached https://files.pythonhosted.org/packages/fc/58/21649fc1849b1f688f3d42e25e79615cc573469ea57eaa9e6af70b1e3b87/web.py-0.39.tar.gz\n Complete output from command python setup.py egg_info:\n Traceback (most recent call last):\n File "<string>", line 1, in <module>\n File "C:\\Users\\KARANJ~2\\AppData\\Local\\Temp\\pip-install-isj4gcc5\\web.py\\setup.py", line 6, in <module>\n from web import __version__\n File "C:\\Users\\KARANJ~2\\AppData\\Local\\Temp\\pip-install-isj4gcc5\\web.py\\web\\__init__.py", line 14, in <module>\n import utils, db, net, wsgi, http, webapi, httpserver, debugerror\n File "C:\\Users\\Karanjit Singh\\AppData\\Roaming\\Python\\Python37\\site-packages\\db\\__init__.py", line 69\n …Run Code Online (Sandbox Code Playgroud) 我想知道为什么在调用函数时不会重新创建局部变量?
#include <iostream>
using namespace std;
void func(void)
{
int a = 0;
cout << &a << endl;
}
int main(void)
{
func();
func();
func();
func();
system("pause");
return 0;
}
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为什么变量a每次都映射到同一个内存地址?